Question

A ball with a density of 1100 kg/m3 is submerged in two liquids: water (ρ = 1000 kg/m3) and honey (ρ = 1400 kg/m3). What will the ball do?
We do not have enough information because we need to know the mass of the ball in order to determine whether it will sink or float.

The ball will sink in both the honey and the water because any solid object will sink in a liquid.

It will sink and accelerate downwards in water. It will float and accelerate upwards in honey.

Objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float.

It will sink and accelerate downwards in honey. It will float and accelerate upwards in water.

Objects with a smaller density than the surrounding liquid sink, while objects with a greater density than the surrounding liquid float.

Answer 1

Hello!

So, we are given a ball with a density of 1100 kg/m³, and two liquids: water (1000 kg/m³) and honey (1400 kg/m³). Our goal is to determine if the ball will sink or float in the given liquids.

Let's take two common substances: water and ice. Water has a density of 1000 kg/m³ and ice has a density of about 917 kg/m³. You would notice that the ice is always floating when you put ice and water together. This would occur if you have other substances.

Here's what you should know:

1. If the density of an object is greater than the liquid it is in, then that object will sink.
2. If the density of an object is less than the liquid it is in, then that object will float.

Since the ball has a density of 1100 kg/m³, and water's density is 1000 kg/m³, then the ball will sink. If the ball is placed in honey, then it will float because the density of honey (1400 kg/m³) is greater than the ball's density.

Therefore, objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float, which is the fourth choice.