
The Correct choices are :
- 1. The elements have filled valence levels.
- 2. potassium (K) with a 1+ charge
Answer:
- <u>21.4 ml (second choice)</u>
Explanation:
<u>1) Data:</u>
a) C₁ = 60.0% (initial solution)
b) V₁ = 30.0 ml (initial solution)
c) C₂ = 0% (pure water)
d) V₂ = ? (pure water)
e) C₃ = 35.0% (final concentration)
<u>2) Formula:</u>
- C₁V₁ + C₂V₂ = C₃V₃
- V₁ + V₂ = V₃ (assuming volume addtivity)
<u>3) Solution:</u>
<u />
a) Substitute values in the first formula:
- 60.0% × 30 ml + 0 = 35% (30 ml + V₂)
b) Solve the equation (units are supressed just to manipulate the terms)
- V₂ = 7.5 / 0.35 = 21.4 ml ← answer
Answer:
2M
Explanation:
M=mol/L
1. Find moles of CoCl2
mass of substance/molar mass = 130/129.833 = 1.001 mol
3. Substitute in molarity equation
M=(1.001/0.5)
M= around 2M
Answer:
<em>249 kJ</em>
Explanation:
To obtain the energy change of the reaction:
H₂O → H₂ + ¹/₂ O₂
It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:
Energy of products:
1 mol of H-H bond × 436 kJ/mol = 436 kJ
¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ
Energy of reactant:
2 mol of H-O bond × 467 kJ/mol = 934 kJ
Energy change of the reaction is:
934 kJ - (436 kJ + 249 kJ) = <em>249 kJ</em>
<em></em>
I hope it helps!
Answer: The standard enthalpy of formation of this isomer of
is -210.9 kJ
Explanation:
The given balanced chemical reaction is,

First we have to calculate the enthalpy of formation of
.

![\Delta H^o=[n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{O_2}\times \Delta H_f^0_{(O_2)+n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CO_2%29%7D%2Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2O%29%7D%5D-%5Bn_%7BO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28O_2%29%2Bn_%7BC_8H_%7B18%7D%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_8H_%7B18%7D%29%7D%5D)
where,
We are given:

Putting values in above equation, we get:
![-511.3kJ/mol=[(8\times -393.5)+(9\times -241.8)]-[(\frac{25}{2}\times 0)+(1\times \Delta H_f^0_{(C_8H_{18})}](https://tex.z-dn.net/?f=-511.3kJ%2Fmol%3D%5B%288%5Ctimes%20-393.5%29%2B%289%5Ctimes%20-241.8%29%5D-%5B%28%5Cfrac%7B25%7D%7B2%7D%5Ctimes%200%29%2B%281%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28C_8H_%7B18%7D%29%7D)
