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Eddi Din [679]
3 years ago
6

please help with this here is the link also https://www.ck12.org/assessment/tools/geometry-tool/plix.html?eId=SCI.CHE.124.5&

questionId=53dfa5538e0e087de33b6cb1&artifactID=1829201&backUrl=%2F%2Finteractives.ck12.org%2Fplix%2Fchemistry%2Findex.html%3Freferrer%3Dteacher%26backUrl%3Dhttp%3A%2F%2Fwww.ck12.org%2Fteacher%2F&isBrowsePage=true&plix_redirect=1

Chemistry
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

ab and e

Explanation:

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Which process takes place in both plant and animal cells?
matrenka [14]
The answer is Cellular respiration because it occurs in the cytoplasm of both plants and animals.
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3 years ago
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5.68 x 10^4 mL to L Express your answer to three sianificant fiqures and includ
olasank [31]

Answer:

5.68 × 10⁴ mL = 56.8 L

Explanation:

Volume is defined as the amount of three-dimensional closed space. The SI unit of volume is cubic metre which is denoted by the symbol m³.

According to the metric system, other units of volume include: litre (L), millilitre (mL) and cubic centimetre (cm³).

Since, 1 mL = 0.001 L = 10⁻³ L

Therefore, 5.68 × 10⁴ mL = 5.68 × 10⁴ × 10⁻³ L = 5.68 × 10 L = 56.8 L

5.68 × 10⁴ mL = 56.8 L, has three non-zero significant figures.

3 0
4 years ago
Two students pull a box with force of 100 N to the left and 200 N to the right.
laiz [17]

Answer:

net force is 100 N and direction is right

Explanation:

7 0
3 years ago
How many moles are represented by 3.01 - 1023 helium atoms?
Pavlova-9 [17]

Answer:

0.5 mol

Explanation:

Given data:

Number of atoms of He = 3.01 ×10²³

Number of moles = ?

Solution:

Avogadro number:  

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.02 × 10²³ is called Avogadro number.

1 mole = 6.02 × 10²³ atoms

3.01 ×10²³ atoms × 1 mol / 6.02 × 10²³ atoms

0.5 mol

7 0
3 years ago
PLS HELP I REALLY NEED IT IM ON THE VERGE OF TEARS
prohojiy [21]

The volume of O₂ : 21 L

<h3>Further explanation</h3>

Given

8.7 grams of C₂H₄

Required

Volume O₂

Solution

Reaction

C₂H₄ + 3 O₂ ⇒ 2 CO₂ + 2 H₂O

mol C₂H₄(MW= 28 g/mol) :

= mass : MW

= 8.7 g : 28 g/mol

= 0.311

From the equation, mol  O₂ :

= 3/1 x mol C₂H₄

= 3/1 x 0.311

= 0.933

At STP, 1 mol gas=22.4 L, so for 0.933 mol :

= 0.933 x 22.4 L

= 20.899 L ≈ 21 L

6 0
3 years ago
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