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anygoal [31]
4 years ago
11

Synthesis gas consists of a mixture of H2 and CO. Calculate at 101kpa is compressed at constant temperature from 7.20 dm3 to 4.2

1 dm3. calculate the final pressure of the gas
Chemistry
2 answers:
bazaltina [42]4 years ago
5 0

Answer:

The final pressure is 173 kPa.

Explanation:

A mixture of gases at an initial pressure of  P₁ = 101 kPa is compressed from an initial volume V₁ = 7.20 dm³ to a final volume V₂ = 4.21 dm³. If we suppose an ideal gas behavior and that temperature remains constant, we can apply Boyle's law to find out the final pressure P₂:

P₁ . V₁ = P₂ . V₂

P_{2}=\frac{P_{1}.V_{1}}{V_{2}}=\frac{101kPa.7.20dm^{3} }{4.21dm^{3} }  =173kPa

cricket20 [7]4 years ago
3 0

Explanation:

According to Boyle's law, volume of a gas is inversely proportional to its pressure at a constant temperature.

Mathematically,    P \propto \frac{1}{V};    at constant T

It is given that,

          P_{1} = 101 kPa,    P_{2} = ?

          V_{1} = 7.20 dm^{3},    V_{2} = 4.21 dm^{3}

We will calculate the final pressure as follows.

           P_{1}V_{1} = P_{2}V_{2}

    101 kPa \times 7.20 dm^{3} = P_{2} \times 4.21 dm^{3}

       P_{2} = \frac{101 kPA \times 7.20 dm^{3}}{4.21 dm^{3}}

                  = 172.73 kPa

Thus, we can conclude that the final pressure of the gas is 172.73 kPa.

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Hello there!
Alenkasestr [34]

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃  →  Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃  with CO₂.

                   Li₂CO₃        :            CO₂

                     1                :               1

                  0.17             :             0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide =   0.17 mol ×  44 g/mol

Mass of carbon dioxide = 7.48 g

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3 years ago
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