The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
The Answer is 12 days or times.
Step-by-step explanation:
The LCM of 6 is 3 and 2, the LCM of 4 is 2 and 1, so we multiply 3 by 2 and 4 by 2 together to get 12, which is the number of days or times.
Is that the question is there any parts to it I mean I guess it’s a plot
Answer:
b
Step-by-step explanation:
Answer:
its c because b is a right angle triangle
thats how i solved it if there is a mistake tell me