Answer:
of water at 30C and 1 atm is 256.834 J/mol·K.
Explanation:
To solve the question, we note the Maxwell relation such as
Where:
= Specific heat of gas at constant pressure = 75.3 J/mol·K
= Specific heat of gas at constant volume = Required
T = Temperature = 30 °C = 303.15 K
α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹
K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹
Therefore,
75.3 - 
= 
= - 75.3 = 256.834 J/mol·K.
D = m / V
0.736 = 225.0 / V
V = 225.0 / 0.736
V = 305.7 cm³
Answer:
0.84 mol
Explanation:
Given data:
Moles of ZnCl₂ produced = ?
Mass of Zn = 55.0 g
Solution:
Chemical equation:
2HCl + Zn → ZnCl₂ + H₂
Number of moles of Zn:
Number of moles = mass / molar mass
Number of moles = 55.0 g/ 65.38 g/mol
Number of moles = 0.84 mol
Now we will compare the moles of Zn with ZnCl₂ from balance chemical equation.
Zn : ZnCl₂
1 : 1
0.84 : 0.84
So from 55 g of Zn 0.84 moles of zinc chloride will be produced.
Answer
<span>How does adding a non-volatile solute to a pure solvent affect the vapor pressure of the pure solvent?
</span>Answer The third option The solvent's vapor pressure will not be affected.
<span>To make a 2.0 M solution, how many moles of solute must be dissolved in 0.50 liters of solution?
Answer C. 1.0 mole solute.
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