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Minchanka [31]
3 years ago
15

use the particle theory to explain why hot chocolate powder dissolves more rapidly in hot water than cold water

Chemistry
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

2) To dissolve, solvent particles must come in contact with solvent particles. Particles of hot water are moving much more rapidly than particles of cold water. Hence, in hot water more water particles will come in contact with hot chocolate powder than in cold water, resulting in faster dissolving.

Explanation:

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What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = pKa? Ka = 1.8×10-5
Westkost [7]

Answer:

a) We have to add 0.9 mole NaOH to 1.0 L of 1.8 M HC2H3O2

b) We have to add 0.277 mole NaOH to 1.0 L of 1.8 M HC2H3O2

c) We have to add 1.16 mole NaOH to 1.0 L of 1.8 M HC2H3O2

Explanation:

a) <em>What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = pKa?</em>

<em />

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = pK = -log(1.8*10^-5) = 4.74

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

4.74 = 4.74 + log(A-/HA)

0 =  log(A-/HA)

A-/HA = 1

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 1

X =0.9

<u>We have to add 0.9 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

To control we can do the following equation:

4.74 = 4.74 + log(0.9/0.9) = 4.74

b)<em> What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 4.00?</em>

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = 4

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

4 = 4.74 + log(A-/HA)

-0.74 =  log(A-/HA)

A-/HA = 0.182

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 0.182

X =0.277

<u>We have to add 0.277 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

<u> </u>

To control we can do the following equation:

4 = 4.74 + log(0.277/1.523)

<em></em>

<em>c) What quantity (moles) of NaOH must be added to 1.0 L of 1.8 M HC2H3O2 to produce a solution buffered at pH = 5.00</em>

Step 1: Data given

Volume of HC2H3O2 = 1.0 L

Molarity of HC2H3O2 = 1.8 M

Ka = 1.8*10^-5

ph = 5

Step 2:

Use the Henderson-Hasselbalch equation.

pH = pKa + log(A-/HA)

5 = 4.74 + log(A-/HA)

0.26 =  log(A-/HA)

A-/HA = 1.82

Consider X = moles of NaOH added (and moles of A- formed)

Remaining moles of HA = 1.8 - X

moles of A- = X

HA = 1.8 - X

X/(1.8-X) = 1.82

X =1.16

<u>We have to add 1.16 mole NaOH to 1.0 L of 1.8 M HC2H3O2 </u>

<u> </u>

To control we can do the following equation:

5 = 4.74 + log(1.16/0.64) = 5

3 0
4 years ago
What fraction of the carbon dioxide exhaled by animals is generated by the reactions of the citric acid cycle
puteri [66]

Answer:

1/3

Explanation:

Pyruvate is produced by the glycolysis in cytoplasm. The oxidation of pyruvate takes place in mitochondrial matrix.  

Pyruvate is converted to acetyl-CoA in the reaction given below:

Pyruvate + NAD⁺ + CoA-SH ⇒ acetyl-CoA + NADH + CO₂

1 molecule of carbon dioxide is eliminated from 1 molecule of pyruvate.

Also,  

2 molecules of carbon dioxide is eliminated from 2 molecules of pyruvate (as glucose on glycolysis yields 2 molecules of pyruvate).

Also, acetyl-CoA further goes into the citric acid cycle and produces 2 molecules of carbon dioxide.

Thus pyruvate produces total 3 molecules of CO₂  and hence glucose produces 6 molecules of CO₂ (as glucose on glycolysis yields 2 molecules of pyruvate)

Thus,

<u>Fraction = 2/6 = 1/3</u>

4 0
4 years ago
5. When argon was discovered, it was placed between chlorine and potassium, even though the periodic
Neporo4naja [7]
Because the modern periodic table is according to icnreasing atomic numbers.Ar has the atomic number 18 and potassium 19 so Argron is placed before K in the Modern periodic table.
4 0
2 years ago
Identify each definition that applies to the compound in red. Check all that apply.
andre [41]

Answer:

Arrhenius acid & Bronsted-Lowry acid

Explanation:

4 0
3 years ago
What is developmental delay? why is it so important to respond promptly when one is suspected?
Vadim26 [7]
Developmental delays is when your child dose not reach there developmental milestones at the expected times...It is important to respond promptly so that the child can get the help they need to help them get back on the right track
8 0
3 years ago
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