Answer:
No
Explanation:
One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.
When one gram phosphorus and 6 gram of iodine react they gives 8.234 g
ram of PI₃ .
Given data:
Mass of phosphorus = 1 g
Mass of iodine = 6 g
Mass of PI₃ = ?
Solution:
Chemical equation:
P₄ + 6I₂ → 4PI₃
Number of moles of P₄:
Number of moles = Mass /molar mass
Number of mole = 1 g / 123.9 g/mol
Number of moles = 0.01 mol
Number of moles of I₂:
Number of moles = Mass /molar mass
Number of moles = 6 g / 253.8 g/mol
Number of moles = 0.024 mol
Now we will compare the moles of PI₃ with I₂ and P₄.
I₂ : PI₃
6 : 4
0.024 :
4/6×0.024 = 0.02
P₄ : PI₃
1 : 4
0.01 : 4 × 0.01 = 0.04 mol
The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.
Mass of PI₃ = moles × molar mass
Mass of PI₃ = 0.02 mol × 411.7 g/mol
Mass of PI₃ = 8.234 g
The correct answer is B.
Lowering of the freezing point can be a colligative property. The greatest concentration of mass of salt in the water will have what we call the lowest freezing point.
For example the least amount of water in the greatest amount of salt.
The reaction is
CH3OH(l)→CH3OH(g)
To calculate ΔG°
ΔG°=ΔG°f of CH3OH(g)-ΔG°f of CH3OH(l)
=162.3kJ/mol - (-166.6kJ/mol
=4.3kJ/mol.
Answer:
The reaction rate is inversely proportional to the reaction time.
Explanation:
- The reaction rate is the change of the concentration of reactants and products with the time.
<em>∵ Reaction rate = - Δ[reactants]/Δt = Δ[products]/Δt.</em>
<em>∴ The reaction rate is inversely proportional to the time, as the reaction rate increases it will take a lower time.</em>
4.88x10^20 H2O2 molecules
