All categories

3 years ago

Triangle ABC has the coordinates A(-3, -2), B(2, 4) and C(2,-2). What is the area of triangle ABC?

Mathematics

1 answer:

Snezhnost [94]3 years ago

3 0

Answer: The area is 15 square units

Step-by-step explanation: It is helpful to sketch the coordinates on a graph to get an idea of what the triangle looks like so you can see which side will be the base, and where to get the height. You will see that AB is the hypotenuse, it is a right triangle, so AC can be the base and BC is the height.

Use the differences in x-values of points C & A to get the length of the base: 2-(-3) is 5

Use the differences in y-values of points B & C to get the height:

4-(-2) = 6

Area = bh/2

A = 5×6/2 = 30/2

A = 15 square unts

You might be interested in

Write the equation of the line passing through the point (-3,-9) and perpendicular to the line x=-4

lisabon 2012 [21]

Answer:

y = -9

Step-by-step explanation:

8 0

4 years ago

Which is bigger -5 or -3

cupoosta [38]

-3 , because it is closer to the "0" in a number line, which makes it greater.

7 0

4 years ago

Read 2 more answers

A triangle has vertices (-1, 2), (3, 1), and (7.2). What is the approximate perimeter of the triangle? Round your answer to the

Inessa [10]

Answer

16.25

Step-by-step explanation: To The Nearest Hundredth

(-1, 2), (3, 1)

√17

(3, 1), (7, 2)

√17

(3, 1), (7, 2)

√8

So our answer is =

8 + √17 + √17 = 16.25

hope it works for you!

7 0

3 years ago

the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t

Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count $Pr(A|B).$

Use formula for conditional probability:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.$

1. The event $A\cap B$ consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $A\cap B$ is

$Pr(A\cap B)=\dfrac{1}{20}.$

2. The event $B$ consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event $B$ is