Answer:
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<span>International System of Units (SI Units) are organized body of measurements for physical quantity. They are set to be the norm or global norm scaling for every physical quantity which includes kilogram, meter, second, ampere, kelvin, candela and mole. These measurements then can increase or decrease by the power of ten, multiplied or divided. As said and explained, the SI is helpful in describing objects because </span>
<span><span>1. </span>They give us the idea of how much matter is contained in that single substance or the current state the matter is in or how hot or cold. We measure and can quantify the quality of the specific matter.</span> <span><span>
2. </span>SI Units are a global set of measurement hence, we can communicate with ease from western to eastern countries with these measurements without having problems in terms of portraying or displaying a set of physical quantities.</span><span>
</span>
Answer:
x = 5
z =2
y =4.4
Step-by-step explanation:
y varies directly as x
y = kx
and inversely as z
y = kx/z
Putting in the numbers in the first line of the table, we can solve for k
13.75 = k * 25/4
Multiply by 4
13.75*4 = 25k
55 =25k
Divide by 25
55/25 = 25k/25
2.2 = k
Now we can fill in the table
y = 2.2 x/z
Row 2 we need to find x
1 = 2.2 x/11
Multiply by 11
11 = 2.2 x
Divide by 2.2
11/2.2 = 2.2x
5 =x
Row 3 we need to find z
18.7 = 2.2 *17/z
18.7 = 37.4 /z
Multiply by z
18.7z = 37.4
Divide by 18.7
18.7/18.7z = 37.4/18.8
z =2
Row 4 we need to find y
y = 2.2 *10/5
y = 22/5
y =4.4
The first step is to determine the zeros of p(x).
From the Remainder Theorem,
p(a) = 0 => (x-a) is a factor of p(x), and x=a is a zero of p(x).
Try x=3:
p(3) = 3^3 - 3*3^2 - 16*3 + 48 = 27 - 27 - 48 + 48 = 0
Therefore x=3 is a zero, and (x-3) is a factor of p(x).
Perform long division.
x² - 16
-------------------------------------
x-3 | x³ - 3x² - 16x + 48
x³ - 3x²
-----------------------------------
- 16x + 48
- 16x + 48
Note that x² - 6 = (x+4)(x-4).
Therefore the complete factorization of p(x) is
p(x) = (x-3)(x+4)(x-4)
To determine when p(x) is negative, we shall test between the zeros of p(x)
x p(x) Sign
---- --------- ---------
-4 0
0 48 +
3 0
3.5 -1.875 -
4 0
p(x) is negative in the interval x = (3, 4).
Answer
The time interval is Jan. 1, 2014 to Jan. 1, 2015.
