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tangare [24]
3 years ago
11

At this point Ron is slightly confused, this isn’t surprising. However, Hermione is doing rather well with them. This also isn’t

surprising since she studies every day, as should all students. She feels she can help him understand these problems by working with him though another: A 1.00 L sample of dry air contains 0.0319 mol N2, 0.00856 mol O2, and 0.000381 mol Ar. If temperature is 25.0◦C what is the partial pressure of N2? Express your answer in atmospheres.
Chemistry
1 answer:
Zigmanuir [339]3 years ago
4 0

Answer:

\boxed{\text{0.780 atm}}

Explanation:

Hermione is pretty smart. She realizes that, according to Dalton's Law of Partial Pressures, each gas exerts its pressure independently of the others, as if the others weren't even there.

She shows Ron how to use the Ideal Gas Law to solve the problem.

pV = nRT

She collects the data:

V = 1.00 L; n = 0.0319 mol; T = 25.0 °C

She reminds him to convert the temperature to kelvins

T = (25.0 +273.15) K = 298.15 K

Then she shows him how to do the calculation.

p \times \text{1.00 L} = \text{0.0319 mol} \times \text{L}\cdot\text{atm}\cdot\text{0.082 06 K}^{-1}\text{mol}^{-1} \times \text{298.15 K}\\\\1.00p = \text{0.7805 atm}\\\\p = \textbf{0.780 atm}\\\\\text{The partial pressure of the nitrogen is } \boxed{\textbf{0.780 atm}}

Isn't she smart?

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Antoine Lavoisier discovered the Law of Conservation of Mass, which states that mass is converted in a chemical reaction. What e
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The answer is D. Nothing

T<span>he only thing that must remain equal as stated in the Law of Conservation of Mass are the same number of atoms of each element on each </span><span>side of a chemical equation. </span>
3 0
4 years ago
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Compound decomposes through the following unbalanced reaction in acidic media: MnO2→ MnO4-(s) + Mn2+(s) Balance this reaction an
choli [55]

Answer:

C) MnO₂

Explanation:

If we write the semi equations (this is, for reduction and oxidation) we will have:

Oxidation: 2MnO₂ → MnO₄⁻ + Mn⁺²

Reduction: 2H₂O → H₂ + 2OH⁻

Then the final global reaction (just adding the two above hemi chemical reactions):

2MnO₂ + 2H₂O → MnO⁻₄ + Mn⁺² + H₂ + 2OH⁻ (in acidic media)

So, we have Mn⁺⁴ (from MnO₂) goes to Mn⁺⁷ and Mn⁺² (this is, Mn is oxidated) and H⁺ (from acidic media or H₂O) goes to H₂ (this is, it is reduced). So the reducing agent would be MnO₂

7 0
4 years ago
The mineral benitoite is a gemstone for making jewelry. It has a molecular weight of 413.44 grams/mole and a percent composition
Mila [183]
<h3>Answer:</h3>

               Option-A (BaTiSi₃O₉)

<h3>Solution:</h3>

Step 1: Calculate Moles of each Element;

                      Moles of Ba  =  %Ba ÷ At.Mass of Ba

                      Moles of Ba  = 33.21 ÷ 137.33

                      Moles of Ba  =  0.241 mol


                      Moles of Ti  =  %Ti ÷ At.Mass of Ti

                      Moles of Ti  = 11.58 ÷ 47.88

                      Moles of Ti  =   0.241 mol


                      Moles of Si  =  %Si ÷ At.Mass of Si

                      Moles of Si  = 20.38 ÷ 28.09

                      Moles of Si  =  0.725 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 34.83 ÷ 16.0

                      Moles of O  =  2.176 mol

Step 2: Find out mole ratio and simplify it;

       Ba                            Ti                                Si                          O

     0.241                       0.241                          0.725                    2.176

 0.241/0.241           0.241/0.241                0.725/0.241            2.176/0.241

         1                             1                                    3                           9 

Hence,  Empirical Formula  =  BaTiSi₃O₉

Step 3: Calculating Molecular Formula:

Molecular formula is calculated by using following formula,

                    Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                     n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  413.44 g.mol⁻¹

Empirical Formula Weight  =  137.33 (Ba) + 47.88(Ti) + 28.09 (Si₃) + 16 (O₉)  =  413.48 g.mol⁻¹

So,

                     n  =  413.44 g.mol⁻¹ ÷ 413.48 g.mol⁻¹

                     n  =  1

Putting Empirical Formula and value of "n" in equation 1,

                    Molecular Formula  = 1 × BaTiSi₃O₉

                   Molecular Formula  =  BaTiSi₃O₉

6 0
4 years ago
Is the reaction to produce zinc from zinc sulfide spontaneous under standard conditions? Coupledreaction: ZnS(s) + H2 (g)  Zn(s
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Answer:

The reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.

Explanation:

Hess's law states: "When one reaction can be expressed as the algebraic sum of others, its heat of reaction is equal to the same algebraic sum of the partial heats of the partial reactions". So Hess's Law is an indirect method of calculating the heat of reaction or enthalpy of reaction when the chemical reaction occurs in one or more than one stage.

Taking into account that ΔG is a state function, which only depends on the initial and final states, its variation in a reaction is calculated by adding the free energies of the reactants and products involved in it when both are in the normal state. That is, at the pressure of 1natm if it is gases or at the concentration of 1 mol / L for substances in liquid solution.

The sum of the fitted equations should give the problem equation. So, if in a "data" reaction a substance is as a reactant and in the reaction that you must obtain is as a product, you must turn the "data" reaction and ΔG will change its sign. In this case, this happen with the reaction 1 (Rxn1):

Rxn1: ZnS (s) → Zn (s) + S (s)          ΔG1°= 201.3 kJ

Rxn2: S (s) + H₂ (g) → H₂S (g)        ΔG2°= -33.4kJ

Adding both reactions (taking into account that certain substances appear sometimes as a reagent and others as a product, so they are totally eliminated if they appear in the same quantities) you get:

ZnS (s) + H₂ (g) → Zn (s) + H₂S (g)

Adding algebraically ΔG1° and ΔG2° you get:

ΔG°= ΔG1° + ΔG2°

ΔG°= 201.3 kJ - 33.4 kJ

ΔG°= 167.9 kJ

If a chemical reaction proceeds with a ΔG <0 the process is  spontaneous. If, on the other hand, ΔG> 0, the reaction is not spontaneous.

Since ΔG>0, <u><em>the reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.</em></u>

6 0
3 years ago
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