In constructing a frequency table, first you'll need to arrange your data from lowest to highest and solve for the following: range, class width, and class size.
Range: Highest Value - Lowest Value in the data set.
= 18 - 0 = 0
Class Width: Square root of the total number of data. In the data set, we have 14 numbers. This is the number of classes.
= sqrt (14) = 3.7 or 4
Class Size: Range divided by Class Width.
=18/4 = 4.5 or 5. There should be five numbers inside each class.
The Frequency Table is below.
Eagles | Frequency
0-4 4
5-9 5
10-14 3
15-19 2
Answer:
59.6
Step-by-step explanation:
:)
Answer:
87.92 rounded to the nearest tenth would be 87.9 because you wouldn't round up unless the number after the 9 was 5 or higher.
Step-by-step explanation:
Das is 20 points per user, just fyi
1. distributive property
recall that a(b+c)=ab+ac
5(3x-4)=5(3x)+5(-4)=15x-20
2. bruh, I can't show that here, wait, nvm, see attachment
3.
100% is double the price
45*2=90
the item will sell for $90 in store
4.
1/2+1/4+1/8=
4/8+2/8+1/8=
7/8
7/8 piazza was eaten
5. see attachment
it ends at 15