Answer:
Point slope form
y - 9 = 4(x-1)
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the points are (1,9) and (-1,1)
slope of the line

m = 
m = 4
<u><em>step(ii):-</em></u>
Equation of the straight line passing through the point (1,9) and slope 'm' = 4
y-y₁ = m( x-x₁)
y - 9 = 4(x-1)
y -9 = 4x-4
4 x - y -4+9 =0
4 x - y +5=0
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
Answer:
2m + 10n - 2p
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(4m + 7n - 6p) - (2m - 3n - 4p)
<u>Step 2: Simplify</u>
- Distribute negative: 4m + 7n - 6p - 2m + 3n + 4p
- Combine like terms (m): 2m + 7n - 6p + 3n + 4p
- Combine like terms (n): 2m + 10n - 6p + 4p
- Combine like terms (p): 2m + 10n - 2p
Answer:
A) 10.38hours
B) 617.95 is the concerntration of CO
Step-by-step explanation:
A) when x=600
T= 0.0002x^2 - 0.316x + 127.9
T= 0.0002(600)^2 -0.316(600) + 127.9
T= 10.38secs
B) to find the concerntration, use Almighty formular
X=-b+-sqrt(b^2-4ac)/2a
0.0002x^2-0.316x-127.9=9
0.0002x^2 - 0.316x + 118.9=0
X= 0.316 +- sqrt(0.316^2) -4(0.0002×118.9)/(2×0.0002)
X= 0.316+(0.68817/0.0004)=962.05 or
X=-0.316 -0.68817/0.0004 =617.95
Therefore X is within the domain of 617.95 is the concerntration
Answer:
SQUARE
Step-by-step explanation:
If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).
Find the following MN, NP, PQ and MQ
Using the formula for calculating the distance between two points
MN = √(6-0)²+(0-4)²
MN = √6²+4²
MN = √36+16
MN = √52
MN = 2√13
NP = √(0-6)²+(-4-0)²
NP = √6²+4²
NP = √36+16
NP = √52
NP = 2√13
PQ = √(-6-0)²+(0-(-4))²
PQ = √6²+4²
PQ = √36+16
PQ = √52
PQ = 2√13
MQ = √(-6-0)²+(0-4)²
MQ = √6²+4²
MQ = √36+16
MQ= √52
MQ = 2√13
Since the length of all the sides are equal, hence the shape is a SQUARE
Answer:
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Step-by-step explanation: