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Vikki [24]
3 years ago
11

Poems are often ambiguous because _____. they have both literal and figurative meaning poets are deliberately complex in their w

riting they are ironic they are meant to be read aloud
Mathematics
1 answer:
Mkey [24]3 years ago
3 0
The answer to the stated question above is letter A.  <span>they have both literal and figurative meaning </span>
Poems are often ambiguous because  <span>they have both literal and figurative meaning </span><span>

Choices to this question are:
A. they have both literal and figurative meaning
B. poets are deliberately complex in their writing
C. they are ironic
D. they are meant to be read aloud</span>
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Is one side of a rectangular fish tank best represented by a point, line, plane, or ray?
Rama09 [41]
It is best represented by a plane.
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3 years ago
The figure below shows a partially completed set of steps to construct parallelogram PQRS:
malfutka [58]

Answer:

Student 2 used the correct steps to construct parallelogram PQRS.

Step-by-step explanation:

Out of all the students, student 2 got all the steps correct.

Fix the compass at Q and draw an arc that intersects side QP.

Without changing the width of the compass, move the compass to R and draw an arc.

Draw a line segment from R that passes through T and intersects the second arc at S.

5 0
3 years ago
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Which of the following graphs represents the equation y+2=3(x-1)
Arturiano [62]

For this case we have the following equation, in a linear way:

y + 2 = 3 (x-1)

This expression can be written in the form y = mx + b

Where "m" is the slope and "b" is the cut point with the y axis.

Rewriting the given expression we have:

y + 2 = 3x-3\\y = 3x-3-2\\y = 3x-5

Thus, the slope is 3 and the cut point is -5.

To graph, we must find two points through which the line passes, so, we perform the following steps:

Step 1:

We do x = 0

y = 3 (0) -5\\y = 0-5\\y = -5

Thus, the point (x1, y1) = (0, -5)

Step 2:

We doy = 0

0 = 3x-5\\5 = 3x

x =\frac{5}{3}

Thus, the point (x2, y2) = (\frac{5}{3},0)

Answer:

See attached image


7 0
3 years ago
Read 2 more answers
Can you please answer the question?
Roman55 [17]

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}

\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}

\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}

\tan \alpha + 1 + \cot \alpha

\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

\frac{1}{\cos \alpha \cdot \sin \alpha} + 1

\sec \alpha \cdot \csc \alpha + 1

The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
The mean of 14 numbers is 49. Removing one of the numbers causes the mean to decrease to 43. What number was removed?
Mademuasel [1]

Answer:

126 was removed.

Step-by-step explanation:

The total before division took place was

Total = mean * 14

mean = 49

Total = 49 * 14

Total = 685

Now you subtract x from the total

685 - x

And divide by 13 [one number is missing]

(685 - x)/13

and the result = 43

(685 - x ) / 13 = 43                Multiply both sides by 13

685 - x  = 43 * 13

685 - x = 559                       Subtract 685 from both sides

- x = - 126                             Multiply by - 1

x = 126

4 0
3 years ago
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