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tensa zangetsu [6.8K]
3 years ago
11

WILL MARK AS BRAINLYIEST If x1 and x2 are solutions to ax2+bx+c=0 where a≠0, then x1+x2=

Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

x1 + x2 = -b/a

The answer is based on "Vieta's Formulas" for the sum and product of roots. In other words, in its simplest form, it states that:

for ax^2 + bx + c = 0

  • x1 + x2 = -b/a
  • x1 × x2 = c/a
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Johann walked 1.2 feet per second. how far, in feet did he walk in 5 seconds
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<span><span>1.       </span>Johann walked 1.2 feet every second.
Find the total feet that Johann walked for 5 seconds.
First, let’s have the given numbers:
=> 1.2 feet
=> 5 second
he walked 1.2 feet in every 1 second. So simply multiply 1.2 x 5 seconds to get the total feet that Johann walks.
=> 1.2 feet x 5 seconds
=> 6,  Thus, Johan walked 6 feet in 5 seconds.
Unit Rate = 1.2 / ft
Unit rate = 6 feet / 5 seconds</span>



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