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3 years ago

What is a role of helpful bacteria

Physics

1 answer:

DedPeter [7]3 years ago

7 0

Answer:

Explanation:

Hundreds of different species of "good" bacteria play a very important role in our health by processing fiber and producing certain vitamins, such as B vitamins, vitamin K, and other nutritive substances. The health-promoting bacteria are called probiotics and are normal inhabitants of the human gastrointestinal tract.

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Three astronauts outside a spaceship and that they decide to play catch. All the astronauts weigh the same on Earth and are equa

guajiro [1.7K]

Answer:

Well concluding there is no gravity their motions would be slow and lightweighted. Let's say they were playing on Earth it would approximately take around 5 to 6 minutes even less, so in space it will approximately take around 10 to 12 minutes may be more but this is just my opinion after using my calculator! Hope this helped!

5 0

3 years ago

1) A tiger leaps horizontally from a 7.5 m high rock with a speed of 4.5 m/s. How far from

Artyom0805 [142]

The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= $\sqrt{2y/g}$

where y is the height and g is the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = $\sqrt{2 * 7.5/9.8}$

= 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

= 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

For further reference:

brainly.com/question/11213880?referrer=searchResults

#SPJ9

8 0

1 year ago

A boat crossing a 153.0 m wide river is directed so that it will cross the river as quickly as possible. The boat has a speed of

Lynna [10]

We have the relation

$\vec v_{B \mid E} = \vec v_{B \mid R} + \vec v_{R \mid E}$

where $v_{A \mid B}$ denotes the velocity of a body A relative to another body B; here I use B for boat, E for Earth, and R for river.

We're given speeds

$v_{B \mid R} = 5.10 \dfrac{\rm m}{\rm s}$

$v_{R \mid E} = 3.70 \dfrac{\rm m}{\rm s}$

Let's assume the river flows South-to-North, so that

$\vec v_{R \mid E} = v_{R \mid E} \, \vec\jmath$

and let $-90^\circ < \theta < 90^\circ$ be the angle made by the boat relative to East (i.e. -90° corresponds to due South, 0° to due East, and +90° to due North), so that

$\vec v_{B \mid R} = v_{B \mid R} \left(\cos(\theta) \,\vec\imath + \sin(\theta) \, \vec\jmath\right)$

Then the velocity of the boat relative to the Earth is

$\vec v_{B\mid E} = v_{B \mid R} \cos(\theta) \, \vec\imath + \left(v_{B \mid R} \sin(\theta) + v_{R \mid E}\right) \,\vec\jmath$

The crossing is 153.0 m wide, so that for some time $t$ we have

$153.0\,\mathrm m = v_{B\mid R} \cos(\theta) t \implies t = \dfrac{153.0\,\rm m}{\left(5.10\frac{\rm m}{\rm s}\right) \cos(\theta)} = 30.0 \sec(\theta) \, \mathrm s$

which is minimized when $\theta=0^\circ$ so the crossing takes the minimum 30.0 s when the boat is pointing due East.

It follows that

$\vec v_{B \mid E} = v_{B \mid R} \,\vec\imath + \vec v_{R \mid E} \,\vec\jmath \\\\ \implies v_{B \mid E} = \sqrt{\left(5.10\dfrac{\rm m}{\rm s}\right)^2 + \left(3.70\dfrac{\rm m}{\rm s}\right)^2} \approx 6.30 \dfrac{\rm m}{\rm s}$

The boat's position $\vec x$ at time $t$ is

$\vec x = \vec v_{B\mid E} t$

so that after 30.0 s, the boat's final position on the other side of the river is

$\vec x(30.0\,\mathrm s) = (153\,\mathrm m) \,\vec\imath + (111\,\mathrm m)\,\vec\jmath$

and the boat would have traveled a total distance of

$\|\vec x(30.0\,\mathrm s)\| = \sqrt{(153\,\mathrm m)^2 + (111\,\mathrm m)^2} \approx \boxed{189\,\mathrm m}$

3 0

2 years ago

In a simulation on earth, an astronaut in his space suit climbs up a vertical ladder. On the moon, the same astronaut makes the

mr Goodwill [35]

Answer:

Gravitational potential energy of the astronaut will change by a greater amount on the earth

Explanation:

Gravitational potential energy is expressed by the formula;

GPE = mgh

This means that the gravitational potential energy is directly proportional to the gravity(g)

Now, from constant values, gravity of moon is 1.62 m/s² while gravity of the earth is 9.81 m/s².

This means that if we plug in the values of g on the earth and g on the moon, the potential energy on the earth would be greater than that of the moon

Thus, gravitational potential energy of the astronaut will change by a greater amount on the earth

8 0

3 years ago

How fast must a 2.70-g ping-pong ball move in order to have the same kinetic energy as a 145-g baseball moving at 31.0 m/s

Helen [10]

Answer:

227 m/s

Explanation:

Kinetic energy formula: