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VMariaS [17]
3 years ago
5

Three astronauts outside a spaceship and that they decide to play catch. All the astronauts weigh the same on Earth and are equa

lly strong. The first astronaut throws the second one toward the third one and the game begins. Describe the motion of the astronauts as the game proceeds. How long will the game last?
Physics
1 answer:
guajiro [1.7K]3 years ago
5 0

Answer:

Well concluding there is no gravity their motions would be slow and lightweighted. Let's say they were playing on Earth it would approximately take around 5 to 6 minutes even less, so in space it will approximately take around 10 to 12 minutes may be more but this is just my opinion after using my calculator! Hope this helped!

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Two bicycle tires are set rolling with the same initial speed of 4.00 m/s along a long, straight road, and the distance each tra
77julia77 [94]

Answer:

The coefficient of rolling friction for the tire under low pressure is 0.0342.

Explanation:

Two bicycle tires are set rolling with the same initial speed of 4.00 m/s

Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.

Here,

u_kmg = ma\\\\a=\mu g

Using third equation of motion as :

v^2-u^2=2as\\\\v^2-u^2=2\mu gs\\\\\mu =\dfrac{v^2-u^2}{2gs}\\\\\mu =\dfrac{4^2-2^2}{2\times 9.8\times 17.9}\\\\\mu=0.0342

So, the coefficient of rolling friction for the tire under low pressure is 0.0342.

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3 years ago
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4 years ago
What was a pattern in nature that contributed to an understanding of atoms?
devlian [24]

the fact that chemicals have different colors

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2 years ago
Use free fall in a sentance
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3 years ago
Read 2 more answers
Floating in deep space, you find yourself at rest next to a small asteroid. You reach out and tap the asteroid with a hammer. Wh
Andrei [34K]

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

4 0
3 years ago
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