Answer:
C 2000v its obviously ans because if o is 1000 2 vo is 2000v
The diagram is in the picture attached.
Options are:
A) 32 °C
B) 70 °C
C) 92 °C
D) 100 °C
In order to find the value required, you need to look at the diagram and follow these steps:
1) search for the value of 70 kPa on the y-axis;
2) move on a horizontal line towards the right until you reach the line D;
3) move on a vertical line down, towards the x-axis;
4) read at what value of °C you are at.
Doing so, you can see that you are at a value a little bit above 90 °C (see picture).
Hence, the correct answer is
C) 92°C.
Given:
u = 8.5 cm
f = -14.0 cm
v = image distance
Using the mirror formula 1/u + 1/v = 1/f
1/8.5 + 1/v = 1/-14.0
Rewrite to solve for v:
v = (8.5 * -14.0) / (8.5 - (-14.0))
v = -119 / 22.5
v = -5.29 cm ( round answer as needed.)
Answer:
position 3
Explanation: HOPE IT HELPED
Acceleration in the east direction: ![-4.2 m/s^2](https://tex.z-dn.net/?f=-4.2%20m%2Fs%5E2)
Acceleration in the north direction: ![9.1 m/s^2](https://tex.z-dn.net/?f=9.1%20m%2Fs%5E2)
Explanation:
In order to find the acceleration of the car in the north and east direction, we need to resolve the acceleration vector into its components along the north and east direction.
Taking east as positive x-direction and north as positive y-direction, the two components of the vector are given by:
![a_x = a cos \theta](https://tex.z-dn.net/?f=a_x%20%3D%20a%20cos%20%5Ctheta)
![a_y = a sin \theta](https://tex.z-dn.net/?f=a_y%20%3D%20a%20sin%20%5Ctheta)
where
is the magnitude of the acceleration
is the angle with the positive x-axis
Substituting, we find the components of the acceleration:
![a_x = (10)(cos 115^{\circ})=-4.2 m/s^2](https://tex.z-dn.net/?f=a_x%20%3D%20%2810%29%28cos%20115%5E%7B%5Ccirc%7D%29%3D-4.2%20m%2Fs%5E2)
![a_y = (10)(sin 115^{\circ})=9.1 m/s^2](https://tex.z-dn.net/?f=a_y%20%3D%20%2810%29%28sin%20115%5E%7B%5Ccirc%7D%29%3D9.1%20m%2Fs%5E2)
Learn more about vector components:
brainly.com/question/2678571
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