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NISA [10]
4 years ago
12

Given the function f(x) = x^3 + x^2 − 2x + 1, what is the resulting function when f(x) is shifted to the left 1 unit?

Mathematics
1 answer:
Vikki [24]4 years ago
7 0
The resulting function g(x) is ...
  g(x) = f(x +1)
  g(x) = (((x +1) +1)(x +1) -2)(x +1) +1
    = ((x +2)(x +1) -2)(x +1) +1
    = (x² +3x)(x +1) +1
    = x³ +4x² +3x +1

The shifted function g(x) is ...
  g(x) = x³ +4x² +3x +1

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Step-by-step explanation:

because why not

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6 0
3 years ago
SOMEONE HELP ME PLEASE
faust18 [17]

Answer:

The answer is either 1, 3, or 5

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
A) How many cups of flour are there in 6 servings? How many cups of flour are there per serving? Show your work. (2 pts)
Serjik [45]
A recipe calls for 1 1/2 cups of flour, 3/4 cup of white sugar, and 1/3 cup of brown sugar. The recipe makes 6 servings

A) How many cups of flour are there in 6 servings? 1 1/2 cups
How many cups of flour are there per serving? Show your work. (2 pts)
1 1/2 ÷ 6 = 3/2 x 1/6 = 3/12 = 1/4 cups for 1 serving

b) How many total cups or sugar (white and brown) are there in 6 servings?
3/4 + 1/3 = 9/12 + 4/12 = 13/12 = 1 1/12
How many cups of sugar are there per serving? Show your work. (2 pts)
1 1/12 ÷ 6 = 13/12 x 1/6 = 13/72 cups of white and brown sugar


c) Suppose you modify the recipe so that it makes 8 servings. How much more flour do you need if you already have enough for 6 servings. Show your work. (2 pts)

Flour for 6 servings = 1 1/2 cups
Flour for 1 serving = 1/4 cups
Flour for 8 servings = 1/4 x 8/1 = 8/4 = 2 cups for 8 servings
3 0
4 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
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