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Pachacha [2.7K]
4 years ago
8

How to solve 11^(n-8) - 5 =54

Mathematics
2 answers:
Scrat [10]4 years ago
8 0
11ⁿ⁻⁸-5=54
add 5 both sides
11ⁿ⁻⁸=59
take log₁₁ bot sides
log₁₁11ⁿ⁻⁸=log₁₁59
n-8=log₁₁59
add 8 to both sides
n=(log₁₁59)+8

scoray [572]4 years ago
6 0

Answer:

Value of n is 9.70 (approx.)

Step-by-step explanation:

Given Expression: 11^{n-8}-5=54

We need to solve the given expression.

Consider,

11^{n-8}-5=54

transpose 5 to RHS

11^{n-8}=54+5

11^{n-8}=59

take log on both sides.

log\,11^{n-8}=log\,59

(n-8)log\,11=1.77

(n-8)\times1.04=1.77

n-8=\frac{1.77}{1.04}

n=1.70+8

n=9.70

Therefore, Value of n is 9.70 (approx.)

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