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bearhunter [10]
2 years ago
5

Is graphing inequalities the same as normal graphing shading?

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
3 0
Yea essentially it is.
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Find the range of the data. scores: 84, 83, 80, 95, 99, 95, 83, 83, 92, 84
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To find the range of these scores, we must take the largest scores and subtract the smallest from it.

The largest score is 99, and the smallest score is 80.

99 - 80 = 19

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3 years ago
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Help 5y^5/y^3 a) 5y^2 b) 5/y^2 c) 5y^8 d) 5y
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Answer:

a) 5y²

Step-by-step explanation:

5 divided by 1 is still 5

y^5/y^3 subtract the exponents since the base is the same

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Andy buys shoes that are on sale for 25% off the regular price. If the sale price is $36.45, what was the regular price of the s
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5 0
3 years ago
Is my answer correct or no? <br> ---&gt; show explanation &amp; details if i am wrong!!!
neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

   the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

  • If the distance is equal to the radius of the circle, then the point is on the circle
  • If the distance is greater than the radius, then the point is outside the circle
  • If the distance is less than the radius, then the point is inside the circle

∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

∵ r = 7

∵ 7\sqrt{2} > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0
3 years ago
A proportional relationship is a linear relationship because the rate of change is constant(and equal to the constant of proport
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The  thing that is required for a <span>proportional relationship would be that no matter what the order of the relationship is, it should be that if the function of x increases then x would increases as well or vice versa. Hope this helps. Have a nice day. Feel free to ask more questions. </span>
7 0
2 years ago
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