So for this you got to remember to do PEMDAS. The answer I got was C
The answer would be B because the 100 stays in there and you are adding 8% per year. Hope this helps.
This equation has no solution where 'a' and 'b'
are both non-zero real numbers.
You said 2a + 2b = 2a
Subtract 2a from each side: 2b = 0
'b' must be zero.
And it doesn't matter what the value of 'a' is.
As long as b=0, 'a' can be any number.
Answer:
There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.
It would be unusual to randomly select a person aged 40 years or older who is male and jogs.
Step-by-step explanation:
We have these following probabilities.
A 13.9% probability that a randomly selected person aged 40 years or older is a jogger, so
.
In addition, there is a 15.6% probability that a randomly selected person aged 40 years or older is male comma given that he or she jogs. I am going to say that P(B) is the probability that is a male.
is the probability that the person is a male, given that he/she jogs. So 
The Bayes theorem states that:

In which
is the probability that the person does both thigs, so, in this problem, the probability that a randomly selected person aged 40 years or older is male and jogs.
So

There is a 2.17% probability that a randomly selected person aged 40 years or older is male and jogs.
A probability is unusual when it is smaller than 5%.
So it would be unusual to randomly select a person aged 40 years or older who is male and jogs.
Answer:
The value of A is 2
Step-by-step explanation:
F = 2 , B = 3 , K = 10
K = F( A + B )
10 = 2(A + 3)
10 = 2A + 6
Now, Subtract 6 from each side we get,
10 - 6 = 2A + 6 - 6
4 = 2A
2A = 4
Now, divide both side by 2 we get,
2A/2 = 4/2
A = 2
Thus, The value of A is 2
<h3><u>
FOR V</u><u>ERIFICATION</u>
<u> ONLY</u> :-</h3>
K = F( A + B )
10 = 2(2 + 3)
10 = 2(5)
10 = 10
L.H.S = R.H.S
Hence Proved!
<u>-TheUnknownScientist</u><u> 72</u>