7x/x-4 * x/x+7
mutiply the numerators together
(7x)(x)= 7x^ 2
mutiply the denominators together
(x-4)(x+7)
(x)(x)(7)(x)= x^2+7x
(-4)(x)(-4)(7)= -4x-28
x^2+7x-4x-28
x^2+3x-28
Answer:
7x^2/x^ 2+3x-28
They can line up 20 different ways
Answer:
first I would combine terms which would give me
-4x-7=-7-4x
then I would get the variable on each side of the equal sign
0=0
lastly I would verify the solution
infinite solutions
Step-by-step explanation:
combining combining like terms would give you negative 4x - 7 which is equal to -7 - 4x. if you were to add 7 on either side and 4 on either side you would get 0 = 0 because this is correct it's infinite solutions
Answer:
1
Step-by-step explanation:
