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3 years ago

Consider the following Expression. 3(x+2)=-5-2(x-3) What is the value of x?

Mathematics

2 answers:

castortr0y [4]3 years ago

8 0

The value of x is equal to -1

Mademuasel [1]3 years ago

4 0

this is

the equation on the math

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Given g(x)=-x-1, find g(-4)

Molodets [167]

Answer:

g(-4)=3

Step-by-step explanation:

g(x)=-x-1

g(-4)=-(-4)-1

g(-4)=4-1

g(-4)=3

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4 years ago

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3 years ago

Please help. In the figure two lines intersect to form the angles shown. What is the value of p

VladimirAG [237]

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4 years ago

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snow_tiger [21]

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3 years ago

A 10-foot ladder leans against a wall so that it is 6 feet high at the top. The ladder is moved so that the base of the ladder t

konstantin123 [22]

Answer:

The top of the ladder is now at 10 ft.

Step-by-step explanation:

At the start, we have a height H=6, a length L=10 and a base B, that has to be calculated by the Pythagorean theorem:

$B^2=L^2-H^2=10^2-6^2=100-36=64\\\\B=\sqrt{64}=8$

The base is moved twice the distance the height moves up.

We called this distance x, so we have:

$L^2=(H+x)^2+(B-2x)^2=H^2+2Hx+x^2+B^2-4Bx+4x^2\\\\L^2=(H^2+B^2)+5x^2+(2H-4B)x\\\\L^2=L^2+5x^2+(2H-4B)x\\\\0=5x^2+(2H-4B)x\\\\5x+(2H-4B)=0\\\\x=\dfrac{4B-2H}{5}=\dfrac{4*8-2*6}{5}=\dfrac{32-12}{5}=\dfrac{20}{5}=4$

The new height (H+x) is

$H'=H+x=6+4=10$

The base travels 2x=8, so the new base B' is 0.

This means that the ladder is all against the wall (L=H').

6 0

3 years ago