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kolbaska11 [484]
3 years ago
7

Zinc reacts with iodine in a synthesis reaction. Using a balanced chemical equation for the reaction, determine the percent yiel

d of a 129.0gram sample of zinc was used and 510.6 grams of product is recovered
Chemistry
1 answer:
Karolina [17]3 years ago
6 0

81.9 % is the percent yield of reaction of zinc with iodine producing ZnI2.

Explanation:

Balanced chemical equation for the reaction:

Zn + I2 ⇒ ZnI2

Data given:

mass of sample zinc = 129 grams  

mass of ZnI2 formed = 510.6 grams (actual yield)

number of moles = \frac{mass}{atomic mass of one mole}

 number of moles of zinc = \frac{129}{65.38}

                                            = 1.97 moles

from stoichiometry

1 mole of Zn reacts to form 1 mole of ZnI2

1.97 moles of Zn will form 1.97 moles of ZnI2

atomic mass of ZnI2 = 319.22 grams/mole

mass of ZnI2 formed = 628.86 grams (theoretical yield)

% yield = \frac{actual yield}{theoretical yield} x100     equation 1

from the reaction,

Putting the values in equation 1

% yield = \frac{510.6}{628.86}  x 100

             =  81.19 % is the % yield.

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Answer:

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Explanation:

The balanced equation for the reaction can be written as:

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From the balanced equation above, 3 moles of ethanol will react with 2 moles of K2Cr2O7.

Therefore, 0.00113 X 3/2 moles of ethanol would have been in the blood of the subject = 0.001695 moles of ethanol.

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The molar mass of ethanol is 46g/mole.

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A Questic
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Answer:

No, it is not feasible because the Gibbs free energy change is positive

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