Which of the following is an Alkaline Earth Metal?

Chemistry

2 answers:

kykrilka [37]3 years ago

5 0

Answer:calcium

Explanation:

alexgriva [62]3 years ago

4 0

Answer:

calcium, yeah the yellow one

You might be interested in

C. identify a set of four possible quantum numbers for the circled electron in manganese (mn). (there is more than one correct a

steposvetlana [31]

Although you have not provided the circled electron, I can help you with a wide explanation.

1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.

2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

3) The most reasonable is that you have been asked to give the possible quantum numbers for an electron in the 4s or 3d.

4) Those are 7 electrons and these are their possible sets of quantum numbers:
i) For the two electrons in 4s:
n is the main energy level so n = 4
l tells the kind of orbital, which is s, so l = 0
ml is also 0 (it can be from -l to + l, so given that l i s0, ml is 0)
ms: one is +/12 and the other is -1/2 (this is the spin number).

ii) For the 5 electrons in 3d

n = 3
l can be 0, 1, or 2
if l = 0, then ml = 0

if l = 1, then ml can be -1, 0 , or 1 (from - l to + l)

ms can be either +1/2 or - 1/2 (spin)

5 0

3 years ago

Ammonia, an important source of fixed nitrogen that can be metabolized by plants, is produced using the haber process in which n

jeyben [28]

Hello!

This is the chemical reaction for the Haber Process:

N₂(g) + 3H₂(g) → 2NH₃(g)

From the chemical coefficients in this reaction and the molar masses, we can write the following conversion factor to calculate the grams of nitrogen that are needed to produce 325 grams of ammonia:

$325gNH_3* \frac{1 mol}{17,031 g}* \frac{1 mol N_2}{2 moles NH_3}* \frac{28,0134 g N_2}{1 mol N_2}=267,29 g N_2$

So, there are 267,29 g of N₂ required to produce 325 grams of ammonia.

Have a nice day!

6 0

3 years ago

At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s

Shalnov [3]

Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$