Answer:
Because both carbon and oxygen are demanded to obey the octet's rule.
Explanation:
Hello.
In this case, recalling the Lewis dot structure of CO₂ which is basically:
We know oxygen has six valance electron whereas carbon four valence electrons, it means that oxygen needs two electrons in order to attain eight electrons and carbon needs four electrons for the same purpose. In such a way, as carbon dioxide contains one carbon atom and two oxygen atoms we infer that each oxygen is providing two electrons for a total of four to allow the carbon obey the octet as well as oxygen and this is attained via two double bonds.
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It has 4 valence electron, all of which are needed to bond with nearest neighbors
However <em>trans</em>-2-Butene does not give a characteristic peak in 1620-1680 cm⁻¹ region but still the presence of carbon double bond carbon can be detected by detecting following peaks in IR Spectrum.
1) 3010-3100 cm⁻¹:
As in trans-2-Butene a hydrogen atoms ate attached to sp² hybridized carbon, therefore the stretching of =C-H (C-H) bond will give a peak of medium intensity in the range of 3010-3100 cm⁻¹.
2) 675-1000 cm⁻¹:
Another peak which is given by the bending of =C-H (C-H) bond with strong intensity will appear in the range of 675-1000 cm⁻¹.
Answer:
Yes
Explanation:
Let's write the reaction as
CV⁺+ OH⁻ ⟶ CVOH
The reaction is first order in [CV⁺] and in [OH⁻], so the rate law is
rate = k[CV⁺][OH⁻]
A bimolecular collision between a crystal violet ion and a hydroxide ion as an elementary step would predict the observed rate law.
However, other plausible mechanisms may predict the same rate law.
