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Andreyy89
3 years ago
12

Which atom in each pair has the larger atomic radius?

Chemistry
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

8. Gold, Au.

Explanation:

Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).

Additionally, the unit of measurement of the atomic radius of chemical elements is picometers (1 pm = 10 - 12 m).

1. Li or K: the atomic radius of lithium is 167 pm while that of potassium is 243 pm.

2. Ca or Ni: the atomic radius of calcium is 194 pm while that of nickel is 149 pm.

3. Ga or B: the atomic radius of gallium is 136 pm while that of boron is 87 pm.

4. O or C: the atomic radius of oxygen is 48 pm while that of carbon is 67 pm.

5. Cl or Br: the atomic radius of chlorine is 79 pm while that of bromine is 94 pm.

6. Be or Ba: the atomic radius of berryllium is 112 pm while that of barium is 253 pm.

7. Si or S: the atomic radius of silicon is 111 pm while that of sulphur is 88 pm.

8. Fe or Au: the atomic radius of iron is 156 pm while that of gold is 174 pm.

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Two waves were analyzed with some high-tech instrumentation. The first wave was found to have a wavelength of 3 x 10 m and the s
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Explanation:

The first wave was found to have a wavelength of 3 x 10⁵ m and the second wave had a wavelength of 3 x 10⁴ m

We need to find which wave have a higher frequency.

The relation between frequency and wavelength is given by :

c=f\lambda

Let f₁ and f₂ be the frequency of wave 1 and wave 2.

f_1=\dfrac{c}{\lambda_1}\\\\f_1=\dfrac{3\times 10^8}{3\times 10^5}\\\\=1000\ Hz

And

f_2=\dfrac{c}{\lambda_2}\\\\f_2=\dfrac{3\times 10^8}{3\times 10^4}\\\\=10000\ Hz

Hence, the wave having less wavelength will have higher frequency. The wave having wavelength 3 x 10⁴ m will have higher frequency.

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3 years ago
A car is traveling at 88 ft/sec. What is the car's speed in miles/hour?
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3 years ago
How many liters of hydrogen gas is produced from 3.712 g of magnesium with 104.2ml of 1.385 mol/L HCL (aq) at SATP? Please show
Licemer1 [7]

Answer:

V=1.61L

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Mg+2HCl\rightarrow MgCl_2+H_2

Next, we compute the reacting moles of each reactants:

n_{Mg}=3.712gMg*\frac{1molMg}{24.305 gMg}=0.153molMg

n_{HCl}=1.385\frac{molHCl}{L}*0.1042L=0.144molHCl

Then, as magnesium and hydrohloric acid are in a 1:2 molar ratio 0.153 moles of magnesium will completely react with 0.306 moles of hydrochloric acid yet we only have 0.144 moles, therefore, limiting reactant is hydrochloric acid. Thus, we compute the produced moles of hydrogen:

n_{H_2}=0.144molHCl*\frac{1molH_2}{2molHCl} =0.072molH_2

Finally, we use the ideal gas equation with T=298K and 1atm (STP conditions) to compute the liters of hydrogen gas:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{0.072mol*0.082\frac{atm*L}{mol*K}*273K}{1atm}\\  \\V=1.61L

Best regards.

3 0
3 years ago
Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide. Ca) + H2O --> Ca(OH)2 In a particular
mars1129 [50]

Answer:

Percent yield = 92.5%

Explanation:

The question asks for the percent yield which can be defined as:

\frac{actual yield}{theoretical yield} .100

Where the actual yield is <em>how much product was obtained</em>, in this case 6.11 g of Ca(OH)₂, and the theoretical yield is <em>how much product could be obtained with the given reactants theoretically</em>, that is if the reaction would work perfectly. So we need to calculate first the theoretical yield.

1. First lets write the chemical equation reaction correctly and check that it is balanced:

CaO + H₂O → Ca(OH)₂

2. Calculate the amount of product Ca(OH)₂ that can be obtained with the given reactants (theoretical yield), which are 5.00g of CaO and excess of water. So the amount of CaO will determined how much Ca(OH)₂ we can obtained.

For this we'll use the molar ratio between CaO and Ca(OH)₂ which we see it is 1:1. For every mol of CaO we'll obtain a mol of Ca(OH)₂. So lets convert the 5.00 g of CaO to moles:

 Molar Mass of CaO: 40.078 + 15.999 = 56.077 g/mol

 moles of CaO = 5.00 g / 56.077 g/mol = 0.08916 moles

As we said before from the molar ratio moles of Ca(OH)₂ = moles of CaO

So the moles of Ca(OH)₂ that can be obtained are 56.077 g/mol

We need to convert this value to grams:

 Molar Mass of Ca(OH)₂ = 40.078 + (15.999 + 1.008)*2 = 74.092 g/mol

Theoretical yield of Ca(OH)₂ = 0.08916 moles x 74.092 g/mol = 6.606 g

3. Calculate the percent yield:

\frac{actual yield}{theoretical yield} .100

Percent yield = (6.11 g / 6.606g) x 100 = 92.5 %

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3 years ago
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