Answer:
(a) The average grade point is 2.5.
(b) The relative frequency table is show below.
(c) The mean of the relative frequency distribution is 0.3333.
Step-by-step explanation:
The given data set is
4, 4, 4, 3, 3, 3, 1, 1, 1, 1
(a)
The average grade point is
Therefore the average grade point is 2.5.
(b)
The relative frequency table is show below:
x f Relative frequency
4 3 
3 3
1 4 
(c)
Mean of the relative frequency distribution is
Therefore the mean of the relative frequency distribution is 0.3333.
Step-by-step explanation:
5x = 19 - 4
5x = 15
x = 15/ 5
= 3
hope it helps!
Answer:
B
Step-by-step explanation:
12% is also known as 0.12 which we can multiply by $98 to get the answer.
(hope this helps)
Answer:
The statement, (1- <em>α</em>)% confidence interval for (μ₁ - μ₂) does not contain zero is TRUE.
Step-by-step explanation:
The hypothesis for a test is defined as follows:
<em>H</em>₀: μ₁ = μ₂ vs. <em>H</em>ₐ: μ₁ ≠ μ₂
It is provided that the test was rejected st the significance level <em>α</em>%.
If a decision is to made using the confidence interval the conditions are:
If the null hypothesis value is not included in the (1 - <em>α</em>)% confidence interval then the null hypothesis will be rejected and vice versa.
In this case the null hypothesis value is:
<em>H</em>₀: μ₁ - μ₂ = 0.
If the value 0 is not included in the (1 - <em>α</em>)% confidence interval for the difference between two means, then the null hypothesis will be rejected.
Thus the statement, (1- <em>α</em>)% confidence interval for (μ1- μ2) does not contain zero is TRUE.
P + s = 200......p = 200 - s
20p + 15s = 3400
20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold
p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
