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3 years ago

What is the quotient of (x^3+3x^2-4x-12) / (x^2+5x+6)?

Mathematics

1 answer:

11111nata11111 [884]3 years ago

8 0

Answer:

<u>The quotient is x -2</u>

Step-by-step explanation:

1. Let's simplify and find out the quotient of the following division:

(x^3+3x^2-4x-12) / (x^2+5x+6)

(x³ + 3x² - 4x - 12)/ (x² + 5x + 6)

(x + 2) (x² + x - 6) / (x + 2) (x + 3) ⇒ Factorizing on the numerator and the denominator

(x² + x - 6) / (x + 3) ⇒ Eliminating (x + 2) on the numerator and the denominator

(x + 3) (x - 2) / (x + 3) ⇒ Factorizing on the numerator

x - 2 ⇒ Eliminating (x + 3) on the numerator and the denominator

<u>The quotient is x -2</u>

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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

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4 years ago

What is the sum of the sequence 152,138,124, ... if there are 24 terms?

N76 [4]

Answer: -216

Step-by-step explanation:

To solve the exercise you must use the formula shown below:

$Sn=\frac{(a_1+a_n)n}{2}$

Where:

$a_1=152\\a_n=a_{24}$

You should find $a_{24}$

The formula to find it is:

$a_n=a_1+(n-1)d$

Where d is the difference between two consecutive terms.

$d=138-152=-14$

Then:

$a_{24}=152+(24-1)(14)=-170$

Substitute it into the first formula. Therefore, you obtain:

$S_{24}=\frac{(152-170)(24)}{2}=-216$

3 0

3 years ago

Read 2 more answers

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3 years ago

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aleksandrvk [35]

Answer:

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Step-by-step explanation:

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3 years ago

A Markov chain has 3 possible states: A, B, and C. Every hour, it makes a transition to a different state. From state A, transit

Sedaia [141]

Answer:

A) distribution of x2 = ( 0.4167 0.25 0.3333 )

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Step-by-step explanation:

Hello attached is the detailed solution for problems A and B

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3 years ago