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ad-work [718]
3 years ago
10

Review the graph of function g(x). On a coordinate plane, y = g (x) has a straight line connecting point (negative 5, 4) and (ne

gative 2, 1), a curved line connected (negative 2, 1) and (0, negative 1), and a straight line connecting (0, negative 1) and (4, negative 2). Determine the value of g–1(4).

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

A

Step-by-step explanation:

yan [13]3 years ago
7 0

Answer:

Option (1)

Step-by-step explanation:

From the graph attached,

Points connecting the graph 'g' are (-5, 4), (-2, 1), (0, -1), (4, -2).

Since, rule to get the points lying on the graph of the inverse of the given function is,

(x, y) → (y, x)

If (x, y) is a point on function 'g' then (y, x) will lie on the inverse of the given function.

By the given rule, points on g^{-1}(x) will be,

(4, -5), (1, -2), (-1, 0), (-2, 4)

Therefore, value of the inverse function at x = 4 will be,

y = g^{-1}(4) = -5

Option (1) will be the correct option.

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Step-by-step explanation:

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Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

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Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

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$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

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$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

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