Question

In a test of the hypothesis

Answer 1

Answer:

Step-by-step explanation:

Given that

sample size =n= 50

x bar = sample mean = 10.8

s = sample std deviation = 3.3

Mean difference = 50-10 = 40

Std error of sample = std dev / sqrt n=$\frac{3.3}{\sqrt{40} } =0.5218$

Since population std dev is not known, we have to use t test

Test statistic t = Mean diff/std error = $\frac{40}{0.5218} =76.66$

df = 39

p value = 0.0000

Since p < 0.09 our significance level, we reject our null hypothesis.

A. There is sufficient evidence to reject Upper H 0 for alpha greater than 0.09