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3 years ago

Generating equivalent expressions

1 answer:

4 0

First you would solve what is in the parentheses so 3x-2x=1x or x. Then you would look to see if there are any like terms throughout the rest of the equation which there aren't. Therefore your answer is x+2y+2.

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Encuentra la velocidad promedio de un móvil que durante su recorrido hacia el Norte tuvo las siguientes velocidades.

yan [13]

The mean or average speed of a mobile moving north is: Vprom= 20.575 m/sec

The average speed of a series of given speed values is calculated by summing each of the speeds and then dividing by the number of speeds , as follows:

Speeds:

V1=18.5m/s

V2=22m/s

V3=20.3m/s

V4=21.5m/s

V avg =?

Average V = ( V1+V2+V3 +V4)/4

Vavg = (18.5m/s + 22m/s +20.3m/s + 21.5m/s)/4

Vavg = 20.575nm/sec

To consult visit: brainly.com/question/11100327

5 0

2 years ago

Which statement describe the function of f(x)=3(1/3)x check all that apply

lakkis [162]

The range of the function is all real numbers greater than 0.

As the domain values increase, the range values decrease.

Each successive output is the previous output divided by 3.

8 0

3 years ago

Read 2 more answers

-3(b-7) pleaseeeeee help mee

kupik [55]

Answer:

-3b - 21

Step-by-step explanation:

You have distribute the -3 to both b and 7. So, you would have to multiply the -3 to both b and 7.

8 0

3 years ago

Find the value of x in the image

Ber [7]

Answer:

Step-by-step explanation:

a pentagon has a total of 540 degrees

105, 115, 110, 180-2x, 180-3x are the interior angles (subtract each from 180 because they're on lines)

540= 105+115+110+(180-2x)+(180-3x)

540=330 +(180-2x)+(180-3x)

210=360-5x

-150=-5x

50=x

4 0

3 years ago

Suppose μ1 and μ2 are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of bra

Stella [2.4K]

Answer:

The 95% confidence interval would be given by $-23.44 \leq \mu_1 -\mu_2 \leq -8.16$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =114.1$ represent the sample mean 1

$\bar X_2 =129.9$ represent the sample mean 2

n1=5 represent the sample 1 size

n2=2 represent the sample 2 size

$s_1 =5.08$ sample standard deviation for sample 1

$s_2 =5.37$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =114.1-129.9=-15.8$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_1 +n_2 -1=5+5-2=8$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that $t_{\alpha/2}=\pm 2.31$