<span> <span><span> <span> <span> <span><span> <span> This is easy all you have to do is fill in the chart on the pdf. here I did it but you have to fill it in on your own. So just go from left to right starting at the top and fill it in, all except the dates which I didn't do.Hope this helped :)<span>
<span><span>
<span> Date, </span>
<span>
High, Temperature
</span>
<span>
Subtract current temperature minus previous temperature,</span><span>Difference, </span>
<span>
Low Temperature, </span>
<span>
Subtract current temperature minus previous temperature, </span>
<span>
Difference, </span>
</span>
<span>
<span>
</span>
<span>
93, </span>
<span>
-N/A-, </span>
<span>
-N/A- ,</span><span>
87, </span>
<span>
-N/A-, </span>
<span>
-N/A-, </span>
</span>
<span>
<span>
</span>
<span>
90 ,</span><span>
93-90=, </span>
<span>
-3 ,</span><span>
79, </span>
<span>
79-87, </span>
<span>
-8 ,</span></span><span><span>
</span>
<span>
93, </span>
<span>
93-90, </span>
<span>
3, </span>
<span>
81 ,</span><span>
81-79, </span>
<span>
2 ,</span></span><span><span>
</span>
<span>
91 ,</span><span>
91-93, </span>
<span>
-2 ,</span><span>
81 ,</span><span>
81-81, </span>
<span>
0, </span>
</span>
<span>
<span>
</span>
<span>
91, </span>
<span>
91-91, </span>
<span>
0, </span>
<span>
79, </span>
<span>
79-81, </span>
<span>
-2, </span>
</span>
<span>
<span>
</span>
<span>
95, </span>
<span>
95-91, </span>
<span>
4 ,</span><span>
79 ,</span><span>
79-79, </span>
<span>
0 ,</span></span><span><span>
</span>
<span>
95, </span>
<span>
95-95, </span>
<span>
0, </span>
<span>
79, </span>
<span>
79-79, </span>
<span>
0.</span></span></span></span><span><span><span><span><span><span><span><span>
</span> <span>
</span></span><span> </span> </span></span></span></span> </span></span></span></span> </span></span></span></span> </span></span>
The bigger number is 15 and the smaller number 7. 15 is 8 more than 7. The sum of 15 and 7 is 22.
Answer:
Depth:
μ =20.2025 km
M = 15.625 km
Range = 47.15 km
σ ≈ 15.92 km
Q₁ = 5.7375 km
Q₃ = 34.6675 km
Magnitude:
μ = 2.08375
M = 1.465
Range, R = 5.17
σ = 1.801485 ≈ 1.8
Q₁ = 0.5625
Q₃ = 3.925
Step-by-step explanation:
The given data are;
Depth 
Magnitude
0.76 0.84
4.93 0.47
8.16 0.35
33.58 1.32
21.2 1.61
35.03 4.57
10.05 5.52
47.91 1.99
For the Depth, we have;
The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km
The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;
0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91
, the median is therefore;
(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km
The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km
The Standard deviation of, σ, is given as follows;
Where;
= The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91
)
N = The total number of data point = 8
Substituting, (using Microsoft Excel) we get;
Q₁ = The first quartile = The (n + 1)/4th = term arranged in increasing order
Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km
Q₃ = The first quartile = The 3×(n + 1)/4th = term arranged in increasing order
Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km
For the magnitude, we have, using the same formulas and procedures as above;
μ = 2.08375
M = 1.465
Range, R = 5.17
σ = 1.801485 ≈ 1.8
Q₁ = 0.5625
Q₃ = 3.925
