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Allisa [31]
3 years ago
15

(45/360)2πr=9π/4

Mathematics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:

r=9

Step-by-step explanation:

45/360=1/8

1/8*2=2/8

2/8=1/4

1/4*pi*r=(9pi)/4

Divide both sides by 1/4 (the fours cancel each other out)

Pi*r=9*pi

Pi cancels each other out

R=9

Hope this helps

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Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
At a football game Jasmine bought a soft pretzel for $2.25 in a bottle of water for $1.50 she paid with a $5 bill how much thing
andrew11 [14]

Answer:

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Step-by-step explanation:    

We have been given that at a football game Jasmine bought a soft pretzel for $2.25 in a bottle of water for $1.50 she paid with a $5 bill.

First of all let us find how much Jasmine spent on soft pretzel and water bottle by adding the cost of both items.

\text{Total amount spent on both items}=2.25+1.50

\text{Total amount spent on both items}=3.75

To find the amount that Jasmine will get as a change we will subtract the amount spent on both items from 5.

\text{Amount of change that Jasmine will get}=5-3.75

\text{Amount of change that Jasmine will get}=1.25

Therefore, Jasmine will get $1.25 back as change.

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Suppose f(x)=x^2 and g(x)=(1/3x)^2 which statement comepare the graph of f(x) to the graph of g(x)
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Answer: c

Step-by-step explanation:

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