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nasty-shy [4]
3 years ago
12

Which is the best estimate of the slope of this graph?

Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0

Answer:

top right

Step-by-step explanation:

aleksandrvk [35]3 years ago
3 0

Answer:

3/4

Step-by-step explanation:

We can find 2 points on the graph.

(2,0) (6,3)

We can find the slope using these two points

m = (y2-y1)/(x2-x1)

   = (3-0)/(6-2)

   =3/4

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Let f be a real-valued function defined on [0,∞), with the properties: f is
USPshnik [31]

im not sure this is right

g'(x) = 6b(-5x + 1)^5 (-5)

g'(x) = -30b(-5x +1)^5

g''(x) = -30b(5)(-5x + 1)^4 (-5)

g''(x) = 750b (-5x +1)^4

g(x) = b(−5x + 1)6 − a

when

g(-x) = b(5x +1)6 - a

g'(x) = -30b(-5x +1)^5 = 0

-5x +1 = 0

x = 15

8 0
2 years ago
Rewrite in simplest terms: 2(-4p-6)-5p2(−4p−6)−5p
irina1246 [14]

Answer: 20p³+30p²-13p-12

Step-by-step explanation:

2(-4p-6)-5p²(-4p-6)-5p

-8p-12+20p³+30p²-5p

20p³+30p²-13p-12

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3 0
3 years ago
Read 2 more answers
△ABCis reflected to form​​ ​△A′B′C′​. The vertices of △ABC are A(3, 1), B(1, 5), and C(6, 9). The vertices of △A′B′C′ are A′(−1,
Blababa [14]

Answer:  D) reflection across y = -x

Explanation:

When we reflect over y = x, we basically swap x and y. So for instance, the point (3,1) becomes (1,3).

When reflecting over y = -x, we will do the same thing but we'll make each coordinate swap in sign from positive to negative (or vice versa). The rule for reflecting over y = -x is (x,y) \to (-y,-x)

So if we apply that rule to point A(3,1) then it becomes A ' (-1, -3).

Similarly, B(1,5) moves to B ' (-5, -1)

Finally, C(6,9) becomes C ' (-9, -6)

5 0
3 years ago
Help find X:_,_ Y:_,_
Ne4ueva [31]
Use desmos it’s easy
7 0
2 years ago
One light-year equals 5.9 x 1012 miles. How many light-years are in 6.79
inna [77]

Option B

The number of light years in 6.79 \times 10^{16} miles is 11508 light years

<em><u>Solution:</u></em>

Given that,

One light-year equals 5.9 x 10^12 miles

Therefore,

1 \text{ light year } = 5.9 \times 10^{12} \text{ miles }

To find: Number of light years in 6.79 \times 10^{16} miles

Let "x" be the number of light years in 6.79 \times 10^{16} miles

Then number of light years in 6.79 \times 10^{16} miles can be found by dividing 6.79 \times 10^{16} miles by miles in 1 light year

\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79 \times 10^{16}}{5.9 \times 10^{12}}\\\\\text{Use the law of exponent }\\\\\frac{a^m}{a^n} = a^{m-n}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = \frac{6.79}{5.9} \times 10^{16-12}\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 1.1508 \times 10^4\\\\\text{Number of light years in } 6.79 \times 10^{16} miles = 11508

Thus number of light years in 6.79 \times 10^{16} miles is 11508 light years

3 0
3 years ago
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