(a) 
gives the height at time 
, so the flare's starting height is given by 
:
(b) There are several ways to find the maximum height of the flare. One is to complete the square and write in vertex form:
That is, describes a parabola whose vertex is located at (9, 406); the coefficient of -5 tells us that the parabola is concave, which means the parabola "opens" downward, and the vertex is a maximum. So the maximum height is 406 m.
(C) The flare hits the ground when 
:
or at about 
and 
. We ignore the negative solution (negative time makes no physical sense).
Answer:
1/11
Step-by-step explanation:
Answer:
232 square feet
Step-by-step explanation:
The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...
yard including walk = (26 ft)(36 ft) = 936 ft²
The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...
yard not including walk = (22 ft)(32 ft) = 704 ft²
The difference in these areas is the area of the walkway:
walkway area = (yard including walk) - (yard not including walk)
= (936 -704) ft² = 232 ft² . . . . area of the walk
_____
Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...
(116 ft)(2 ft) = 232 ft²
Answer: sin(B)= h/c
h= csin(b)
Area= 1/2acsin(B)
Step-by-step explanation: i got the answers frfr on edge smh yall know how that is
Answer:
![\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E2%7D%7D)
Step-by-step explanation:
![a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bn%7D%7Bm%7D%3D%5Csqrt%5Bm%5D%7Ba%5En%7D%5C%5C---------------------%5C%5C%5C%5C%5Cleft%285%5Ctimes%5Cdfrac%7B3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Cleft%28%5Cdfrac%7B5%5Ctimes3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B%5Cleft%28%5Cdfrac%7B15%7D%7B4%7D%5Cright%29%5E2%7D)
Answer:
Step-by-step explanation:
![\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5](https://tex.z-dn.net/?f=%5Cleft%285%5E%5Cfrac%7B3%7D%7B4%7D%5Cright%29%5E%5Cfrac%7B2%7D%7B3%7D%5C%5C%5C%5C%5Ctext%7BUse%7D%5C%20%28a%5En%29%5Em%3Da%5E%7Bnm%7D%5C%5C%5C%5C5%5E%7B%5Cfrac%7B3%7D%7B4%7D%5Ccdot%5Cfrac%7B2%7D%7B3%7D%7D%3D5%5E%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B1%7D%7D%3D5%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%5B2%5D5%3D%5Csqrt5)
