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Harman [31]
3 years ago
12

What's another word for x?a. rangeb. domainc. neither​

Mathematics
2 answers:
levacccp [35]3 years ago
3 0

Answer:

probably domain idk im not american

avanturin [10]3 years ago
3 0
Another word for X is Domain
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I can't figure this question out. 50 points if you can answer this for me!
kiruha [24]

(a) h(t) gives the height at time t, so the flare's starting height is given by h(0):

h(0)=-5(0)^2+90(0)+1=1\,\mathrm m

(b) There are several ways to find the maximum height of the flare. One is to complete the square and write h(t) in vertex form:

-5t^2+90t+1=-5(t^2+18t)+1=-5(t^2-18t+81-81)+1=-5(t-9)^2+406

That is, h(t) describes a parabola whose vertex is located at (9, 406); the coefficient of -5 tells us that the parabola is concave, which means the parabola "opens" downward, and the vertex is a maximum. So the maximum height is 406 m.

(C) The flare hits the ground when h(t)=0:

-5t^2+90t+1=0\implies t=9\pm\sqrt{\dfrac{406}5}

or at about t\approx-0.011 and t\approx18.01. We ignore the negative solution (negative time makes no physical sense).

6 0
4 years ago
Write 13/143 as a unit rate
vodomira [7]

Answer:

1/11

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A rectangular yard measuring 26 ft by 36 ft is bordered (and surrounded) by a fence. Inside, a walk that is 2 ft wide goes all t
cestrela7 [59]

Answer:

  232 square feet

Step-by-step explanation:

The outside dimensions of the yard are 26 ft by 36 ft, so its total area is ...

  yard including walk = (26 ft)(36 ft) = 936 ft²

The dimensions of the yard inside the walkway are 22 ft by 32 ft, so that area is ...

  yard not including walk = (22 ft)(32 ft) = 704 ft²

The difference in these areas is the area of the walkway:

  walkway area = (yard including walk) - (yard not including walk)

  = (936 -704) ft² = 232 ft² . . . . area of the walk

_____

Another way to figure this is to consider the length of the centerline of the walkway. That is the perimeter of a rectangle that is 24 ft by 34 ft. The perimeter (centerline length) is 116 ft, and the width of the walk is 2 ft, so its area is ...

  (116 ft)(2 ft) = 232 ft²

4 0
3 years ago
The altitude of the triangle ABC, segment DA, has been
slavikrds [6]

Answer: sin(B)= h/c

h= csin(b)

Area= 1/2acsin(B)

Step-by-step explanation: i got the answers frfr on edge smh yall know how that is

3 0
3 years ago
Read 2 more answers
Rewire the rational exponent as a radical
Mice21 [21]

Answer:

\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}

Step-by-step explanation:

a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}

Answer:

\large\boxed{C.\ \sqrt5}

Step-by-step explanation:

\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5

5 0
3 years ago
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