Question

Identify the vertex of the quadratic function in standard form y=2x^2 -16x+31

Answer 1

Answer:

(4,1)

Step-by-step explanation:

The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).

To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.

To find the y-coordinate, input the x=4 and solve for y.

$y=2(4)^2-16(4)+31\\y=2(16)-64+31\\y=32-64+31\\y=1$

The vertex is (4,1).