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2 years ago

Please answer this question(picture included)

Mathematics

1 answer:

zlopas [31]2 years ago

4 0

2xy^2 + 8y => 2y ( xy +4)

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il63 [147K]

Answer:

Wsp

Step-by-step explanation:

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3 years ago

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-7 times -8? -40 divided by 10?

alekssr [168]

-7 times -8 is 56 and -40 divided by 10 is -4

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2 years ago

Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len

Rama09 [41]

The length of a curve C parameterized by a vector function r(t) = x(t) i + y(t) j over an interval a ≤ t ≤ b is

$\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt$

In this case, we have

x(t) = exp(t ) + exp(-t ) ==> dx/dt = exp(t ) - exp(-t )

y(t) = 5 - 2t ==> dy/dt = -2

and [a, b] = [0, 2]. The length of the curve is then

$\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt$

$=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt$

$=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt$

$=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt$

$=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}$

5 0

2 years ago

Tell me which number you doing so I know what one your doing

liubo4ka [24]

Answer:

here you go

Step-by-step explanation:

1: equal to

2: the answer of two numbers added together is the sum

3: answer to a multiplication problem

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2 years ago

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Please answer this in two minutes

NeTakaya

Answer:

Step-by-step explanation:

Use the Pythagorean Thereom:

$r^{2}$ = $9^{2}$ + $12^{2}$

$r^{2}$ = 81+144

$r^{2}$ = 225

$r$ = 15

Please mark me as Brainliest!

8 0

2 years ago