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Diano4ka-milaya [45]
3 years ago
15

The work of a student to solve a set of equations is shown:

Mathematics
1 answer:
butalik [34]3 years ago
8 0
Step 2! The reason for that is the student didnt multiplied (15-2z) with -2. But she should have!
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This is due tomorrow and i have answers but i think ive done it wrong! please help
Eva8 [605]

Answer:  i) 1 - 9x² - 12x

               ii) 17 - 3x²

             iii) - 20 + 10x² - x⁴

<u>Step-by-step explanation:</u>

g(x) = 3x + 2       h(x) = 5 - x²

i) h(g(x))

  h(3x + 2) = 5 - (3x + 2)²

                  = 5 - (9x² + 12x + 4)

                  = 5 - 9x² - 12x - 4

                  = 1 - 9x² - 12x

ii) g(h(x))

   g(5 - x²) = 3(5 - x²) + 2

                 = 15 - 3x² + 2

                 = 17 - 3x²

iii) h(h(x))

   h(5 - x²) = 5 - (5 - x²)²

                 = 5 - (25 - 10x² + x⁴)

                 = 5 - 25 + 10x² - x⁴

                 = -20 + 10x² - x⁴

4 0
3 years ago
At the end of the current year, Accounts Receivable has a balance of $4,375,000; Allowance for Doubtful Accounts has a debit bal
Advocard [28]

Answer:

$226,300

Step-by-step explanation:

Given Allowance for Doubtful Accounts is estimated as $205,000 and Allowance for Doubtful Accounts has a debit balance of $21,300

#The  amount of the adjusting entry for uncollectible accounts is calculated as below:

Adjustment \ Cost=Allowance\ Doubtful\ Accounts +Doubtful \ Accounts \ Debit \ Balance\\\\=205000+21300\\\\\$226,300

Hence,  the amount of the adjusting entry for uncollectible accounts is $226,300

8 0
2 years ago
HELP! A S A P! ONLY ANSWER IF YOU'RE 100% SURE.
Sidana [21]

ANSWER

Three (3) cartons of juice





Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4

So he can afford 3 juice cartons
6 0
3 years ago
The factorization of 8x3 – 125 is (2x – 5)(jx2 + kx + 25). What are the values of j and k
Inga [223]

Answer:

j=4\\k=10

Step-by-step explanation:

8x^3 - 125

\left(2x\right)^3-5^3

Use this formula:

x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

Where,

x=2x\\y=5

Substitute in the values.

\left(2x\right)^3-5^3=\left(2x-5\right)\left(2^2x^2+5\cdot \:2x+5^2\right)

\left(2x-5\right)\left(4x^2+10x+25\right)

4 0
3 years ago
What shapes will appear in net for a rectangular prism that is not a cube? How many of the ships will there be?
Lyrx [107]
There would be 6 shapes, and it would depend on what those shapes are since you wouldn't know the measurements.
6 0
3 years ago
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