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Otrada [13]
3 years ago
13

Im to layz to do my test so ye all the questions worth 10 points

Mathematics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

subtract 6 from 27 the divide by 3

Step-by-step explanation:

You might be interested in
Who can help me d e f thanks​
12345 [234]

d)

y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}

Product rule:

y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'

Chain and power rules:

y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'

Power rule:

y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)

Now simplify.

y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

e)

y = \dfrac{3bx + ac}{\sqrt{ax}}

Quotient rule:

y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}

y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}

Power rule:

y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}

Now simplify.

y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}

y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}

y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}

f)

y = \sin^2(ax+b)

Chain rule:

y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'

y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'

y' = 2a \sin(ax+b) \cos(ax+b)

We can further simplify this to

y' = a \sin(2(ax+b))

using the double angle identity for sine.

7 0
2 years ago
What’s the correct answer for this?
AysviL [449]

Answer:

B.

Step-by-step explanation:

First angle 1 and 2 add up to 180 and then angle 2 and 3 also add up to 180. So angle 2 is common hence both are congruent to each other.

8 0
3 years ago
The point at which the slope of the tangent line is -3
AlexFokin [52]
F(x) = 6x^2 + 3x - 6

The derivative, and thus the slope of the T. L. to the graph, is f '(x) = 12x + 3.  Set this result = to -3 and solve for x:

12x + 3 = -3  =>  12x = - 6 and x = -1/2
                                                                       6 + 6 - 24
If x = -1/2, y = f(-1/2) = 6(1/4) - 3(-1/2) - 6 = -----------------  = -6
                                                                             4

The slope of the T. L. to the graph will be -3 at the point (-1/2, -6). 
4 0
4 years ago
If angle 4 is x + 15 and angle 2 is 3x - 5, what is the<br> value of x?
Kamila [148]

Answer:

I cant tell what u mean but if the angles are equal the answer is 10

Step-by-step explanation:

4 0
3 years ago
Can someone help me?
Rama09 [41]
Look up on yt how to find those. They r pretty easy.
7 0
2 years ago
Read 2 more answers
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