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Cerrena [4.2K]
3 years ago
13

Isaac invested $1,800 in an account paying an interest rate of 4.7% compounded continuously. Assuming no deposits or withdrawals

are made, how much money, to the nearest hundred dollars, would be in the account after 15 years?
Mathematics
1 answer:
valkas [14]3 years ago
7 0

Answer:

First, convert R as a percent to r as a decimal

r = R/100

r = 4.7/100

r = 0.047 rate per year,

Then solve for A,

              A = P\cdot e^{rt}\\\\A= 1800 \cdot (2.71828)^{(.047)(15)}, \ where \ e = 2.71828\\A = 3642.92  

The amount he receives after 15years $3,642.92

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What is the value of x in the equation 2x+3y=36 when y is 6​
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The annual tuition at a specific college was $20,500 in 2000, and $45,4120
nika2105 [10]

Answer: the tuition in 2020 is $502300

Step-by-step explanation:

The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = $20500

The fee in 2018 is the 19th term of the sequence. Therefore,

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n = 19

Therefore,

454120 = 20500 + (19 - 1) d

454120 - 20500 = 19d

18d = 433620

d = 24090

Therefore, an

equation that can be used to find the tuition y for x years after 2000 is

y = 20500 + 24090(x - 1)

Therefore, at 2020,

n = 21

y = 20500 + 24090(21 - 1)

y = 20500 + 481800

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6 0
3 years ago
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A because it shows you the full amount
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