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butalik [34]
3 years ago
11

The point given is on the terminal side of an angle theta. Find the exact values of the six trig functions of theta.. (-3,2)

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0
We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h =\sqrt{(-3) ^{2}+2^{2} } =  \sqrt{9+4}= \sqrt{13}
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2 
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