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Shkiper50 [21]
3 years ago
7

Marilyn uses a credit card with a 19.9% APR compounded monthly to pay for car repairs totaling $991.38. She can pay $410 per mon

th on the card. What will the total cost of this purchase be?
$1,021.01

$1,188.66

$991.38

$1,192.39

Mathematics
1 answer:
Leokris [45]3 years ago
8 0
Marilyn's finance charge at the end of the first month will be
  $991.38 × 0.199/12 = $16.44
The balance subject to the next month's finance charge will be
  $991.38 +16.44 -410.00 = $597.82

The finance charge at the end of the second month will be
  $597.82 × 0.199/12 = $9.91
The balance remaining after the second payment will be
  $597.82 +9.91 -410.00 = $197.73

The finance charge applied at the end of the third month is
  $197.73 × .199/12 = $3.28
so Marilyn can make one final payment of
  $197.73 +3.28 = $201.01
to pay off the balance.

In all, Marilyn has paid 2×$410.00 +201.01 = 
  $1021.01 . . . . . . . . corresponds to the first choice

_____
In real life, Marilyn's credit card may not accrue any finance charge until after the first statement on which the charge appears. Thus the total cost of the purchase may be only $1004.02. The attached spreadsheet shows the beginning balance and the finance charges for each month for the two different scenarios.

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There is a competition in the cinema to win free tickets. You must guess the ages of the four employees. Here are the clues: - W
jenyasd209 [6]

Answer:

Kirk is <u>28</u> years old, Brian is <u>36</u> years old, Matt is <u>18</u> years old, and the manager is <u>24</u> years old.

Step-by-step explanation:

Let k be Kirk's age.

Let b be Brian's age.

Let m be Matt's age.

Let m_{1} be the boss/manager's age.

From the information given, we can set up 4 equations:

k+b+m+m_{1}=106

k=2(m_{1}-10)

b=2m_{1}-12

m=\frac{1}{2}m_{1}+6

Rewrite the first equation, substituting k, b, and m in terms of m_{1} to get:

2(m_{1}-10)+(2m_{1}-12)+(\frac{1}{2}m_{1}+6)+m_{1}=106

Open up the parentheses using the distributive property (which is a(b-c)=ab-ac) and combine like terms to get:

5.5m_{1}-26=106

Add 26 to both sides to reach:

5.5m_{1}=132

Thus, m_{1}=24. Substitute 24 for m_{1} in the second, third, and fourth original equations to find that k=28, b=36, and m=18. Therefore, Kirk is <u>28</u> years old, Brian is <u>36</u> years old, Matt is <u>18</u> years old, and the manager is <u>24</u> years old. To check, you can add up all of the ages to get 106.

Hope this helps :)

8 0
2 years ago
The taste test for PTC (phenylthiourea) is a common class demonstration in the study of genetics. It is known that 70% of the Am
AysviL [449]

Answer:

The variance for the number of tasters is 4.2

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are tasters, or they are not. The probability of a person being a taster is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The variance of the binomial distribution is:

V(X) = np(1-p)

It is known that 70% of the American people are "tasters" with the rest are "non-tasters". Suppose a genetics class of size 20

This means that p = 0.7, n = 20

So

V(X) = np(1-p) = 20*0.7*0.3 = 4.2

The variance for the number of tasters is 4.2

7 0
3 years ago
I need help please.
Sidana [21]

Answer:

-1/63y^11

Step-by-step explanation:

because we multiply it

7 0
3 years ago
Assuming Earth to be a sphere of radius 4000 miles, how many miles north of the Equator is City A, if it is 36° north from the E
vredina [299]

Answer:

2513 miles

Explanation:

\sf Length \ of \ arc = \dfrac{\theta}{360} * 2\pi r

Here given:

∅ = 36°

radius = 4000 miles

Insert following:

\sf \rightarrow  \dfrac{36}{360} * 2\pi (4000)

\sf \rightarrow  800\pi \  \ \ (in \ terms \ of \ \pi )

\sf \rightarrow  2513.3 \ \ (rounded \ to \ nearest \ tenth)

\sf \rightarrow  2513 \ \ (rounded \ to \ nearest \ mile)

5 0
2 years ago
Of the original 56 signers of the declaration of independence four of them are present in North Carolina if you selected one sig
kari74 [83]
The chance of you selecting one randomly is 4/56, which simplifies to 1/14.
8 0
3 years ago
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