The number of times Ken visits, given the £3.6 pool charge, and 1/3 savings per visit is 5 times.
<h3>Which method can be used to find the number of times Ken visits the pool to get back his £5?</h3>
The entry fee = £3.60
Amount saved on entry fee by having a membership card = 1/3 of the entry fee
Amount Ken spends on the membership card and the reduced entry fee = £5
Therefore;
Reduced entry fee = £3.60×(1 - 1/3) = £2.4
Amount saved per visit = £3.6 - £2.4 = £1.2
The number of visits, <em>n</em>, before he gets back his £5 is therefore;
- n = £5/(£1.2/visit) ≈ 4.17 visits
Ken has to visit the swimming pool more than 4 times to get his £5 back.
Rounding to the next larger whole, therefore;
- The number of visits, n, before he gets back his £5 is 5 visits
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Answer: 7
Step-by-step explanation: First, simplify what's inside the parentheses.
(3 + 3) simplifies to 6 and (-2 + 3) simplifies to 1.
Now we have 6 + 1 or 7.
Answer:
a < b < c
Step-by-step explanation:
The side opposite the larger angle measure is the longer side.
The side opposite the smallest angle measure is the shortest side.
The sum of the three angles = 180° ; (75° + 35° + ? = 180°). The missing angle is 70°
The angles in order from the smallest to the largest:
35° < 70° < 75°
The side for the shortest to the largest
side opposite 35° is a
side opposite 70° is b
side opposite 75° is c
Answer a < b < c
Answer:
<em>10000 times as much</em>
Step-by-step explanation:
If we were to determine how many times larger it is, we can simply divide the two expressions;
5 × 10^6 / 5 × 10^2,
10^6 / 10^2,
10^6 - 2,
10^4; <em>Answer : 10^4 times as much; in other words 10000 times as much</em>
