The answer is
the vector PQ has (4-1, 8-2) as components, so it is vecPQ= (3, 6)
using the definition
the distance PQ= sqrt ( 3²+6²)= sqrt(9+36)=sqrt(45)
Step-by-step explanation:
<u>Given coordinates of the rectangle ABCD:</u>
- A(0, 0), B(a, 0), C(x, y), D(0, b)
Lets first find coordinates of C
We can see that A and B are on same line horizontally, so C and D will be on the parallel line
The distance AB and CD are equal also distance AD and BC are equal, therefore
- AB = a - 0 = a, CD = a
- AD = b - 0 = b, BC = b
<u>So the coordinates of C are:</u>
<u>Now the diagonals:</u>
- AC = √(a-0)² + (b-0)² = √a²+b²
- BD =√(0-a)² + (b -0)² = √a² + b²
Since AC = BD, we can state they are congruent
The lawn area of uniform width can be written as follows:
A = (40 + 2x) * (35 + 2x) - (40) * (35)
Where,
x: width of the lawn
Substituting the value of the area we have:
316 = (40 + 2x) * (35 + 2x) - (40) * (35)
Rewriting:
316 = 1400 + 80x + 70x + 4x ^ 2 - 1400
Rewriting we have:
4x ^ 2 + 150x - 316 = 0
Solving the polynomial we have:
x1 = - 79/2
x2 = 2
Taking the positive root we have that the grass width des:
x = 2 yards
Answer:
The width of the lawn that surrounds the garden is:
x = 2 yards
