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guajiro [1.7K]
3 years ago
12

Why might a dry atmosphere cause your crystal to fracture and to eventually become a

Chemistry
1 answer:
bagirrra123 [75]3 years ago
4 0

Causes when dry atmosphere create crystal to white powder is explained below.

Explanation:

Efflorescence is the loss of water from the chemical structure of a mineral. A small number of hydrous minerals may partially lose the water in their structure if kept in dry or hot areas. This causes the mineral to form a white powder on its surface, and decreases its transparency.

The technical name for this white powder is Efflorescence (from the French, meaning “to flower out”).  It is an accumulation of minerals and salts on masonry surfaces, such as brick, cement, and sometimes stone. Building inspectors and home owners should know how to prevent  and remove this unsightly residue. They must also be aware that, while efflorescence in itself is not a problem, it is a symptom of a problem, namely the presence of excess water in the masonry, which can lead to more serious structural and health issues.

During the summer, it is not unusual for the temperature in these attics to run around 160 – 165 F.  Long story short, I sweat alot because of this.  I wear a cap (below) to keep insulation out of my hair, bit it also acts to absorb the sweat from my forehead and keep it out of my eyes.  This sweat (which is just salt water) is wicked up the cotton fabric of the hat and the water evaporates.  As it does, it leaves the salt behind, creating white stains on the cap.  This is the human form of efflorescence.

As with mold, the appearance of efflorescence varies greatly. It can be powdery, it can have sharp edges and be easy to spot, or it can have indistinct edges. It can cover a large area as a fine dust, or form large individual crystals. Its appearance depends partly on the type of salt from which it is composed, but also on humidity levels (both inside and outside the house), and local rainfall and winter temperatures during the last few years. In exceptionally dry climates, water can evaporate before it even reaches the surface, in which case the salt will accumulate unseen beneath the surface. In humid areas, moisture may take a long time to evaporate, allowing the slow growth of “whispers” projecting from the surface.

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Answer : The value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

Explanation :

The following equilibrium reactions are :

(1) 2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2 K_1=5.40\times 10^{-16}

(2) 2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l) K_2=1.06\times 10^{10}

(3) CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g) K_3=2.68\times 10^{-9}

The final equilibrium reaction is :

CO_2(g)\rightleftharpoons C(s)+O_2(g) K_{goal}=?

Now we have to calculate the value of K_{goal} for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

K_{goal}=\sqrt{K_1\times K_2\times K_3}

Now put all the given values in this expression, we get :

K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}

K_{goal}=1.238\times 10^{-7}

Therefore, the value of K_{goal} for the final reaction is, 1.238\times 10^{-7}

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The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

<h3>How to calculate volume?</h3>

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

  • V1 = 9L
  • V2 = ?
  • T1 = 325K
  • T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: brainly.com/question/2817451

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2 years ago
The following reaction, catalyzed by iridium, is endothermic at 700 K: CaO(s) + CH4(g) + 2H2O (g) → CaCO3 (s) + 4H2 (g) For the
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Answer:

A. Increasing the temperature will favor forward reaction and more CaCo3 formed.

B. More CaCo3 will be formed.

C. CaCo3 will decrease and more react ants formed.

D. Less CaCo3 will be formed.

E. Iridium is a catalyst so there is no effect

Explanation:

A. Temperature will increase because it's an endothermic reaction.

B. Adding Cao will favor forward reaction and more CaCo3 formed.

C. Removing methane, more react ants are formed and CaCo3 decreases.

D. Irridi is a catalyst so it has no effect on the CaCo3 but only speeds its rate of reaction.

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