The (B) answer (B) is (B) (B) (B)
Moles are the division of the mass and the molar mass. The moles of mercury (ii) oxide in the decomposition reaction needed to produce oxygen are 0.781 moles.
<h3>What is a decomposition reaction?</h3>
A decomposition reaction is a breakdown of the reactant into simpler products. The decomposition of mercury (ii) oxide can be shown as:
2HgO(s) → 2Hg(l) + O₂(g)
From the reaction, it can be said that 2 moles of mercury (ii) oxide decomposes to produce 1 mole of oxygen.
The moles of oxygen that needs to be produced are calculated as:
Moles = mass ÷ molar mass
= 12.5 gm ÷ 32 gm/mol
= 0.39 moles
0.39 moles of oxygen are needed to be produced.
From the stoichiometric coefficient of the reaction, the moles of HgO is calculated as: 2 × 0.39 = 0.781 moles
Therefore, 0.781 moles of HgO are required in the reaction.
Learn more about moles here:
brainly.com/question/3801333
#SPJ4
Answer:
CuSO4(aq)
Explanation:
The aqueous form of copper sulfate will conduct electricity.
The Solid form will not be a good conductor.
C₅H₁₂ will not conduct electricity
CO₂ will not conduct electricity
- Copper sulfate is an ionic compound
- In aqueous solutions or molten forms, ionic compounds can conduct an electric current using free mobile ions as carriers.
- This way, they are electrolytes.
- In solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
Answer: Option (A) is the correct answer.
Explanation:
Elements present in group 1 are known as alkali metals. Whereas elements present in group 2 are called alkaline earth metals and elements from group 11 to 12 are transition metals.
As it is known that metals have the ability to lose electrons in order to attain stability and electricity is the flow of electrons from one point to another.
Therefore, metals are good conductors of heat and electricity.
Thus, we can conclude that the statement it’s between groups 1 to 12 because it is metal best explains the probable position of the substance in the periodic table.