I am pretty sure the answer is D. That the patterns of a polarity matched up on both sides.
Answer:
0 g.
Explanation:
Hello,
In this case, since the reaction between methane and oxygen is:

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

Regards.
Answer:
Copper ions are reduced into copper atoms.
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Explanation:
During electrolysis, the positive H⁺ and Cu⁺ ions move to the negative cathode and negative OH⁻ and Cl⁻ ions move to the positive anode.
At cathode, copper ions are preferentially discharged due to the low electromotive force required to discharge them compared to the hydrogen ion. The copper ions gain the two electrons lost by the chloride ions when the are discharged. (2 Cl⁻₍aq₎ → Cl₂₍g₎ + 2e⁻)
Thus the half equation is as follows:
Cu²⁺₍aq₎ + 2e⁻ → Cu₍s₎
Answer:
Explanation:
Given parameters:
Molarity of KOH = 0.26M
Volume of H₂SO₄ = 19.76mL
Molarity of H₂SO₄ = 0.20M
Unknown:
Volume of KOH = ?
Solution:
This is a neutralization reaction in which an acid reacts with a base to produce salt and water:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
We solve from the known to the unknown in the reaction.
The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:
Number of moles of acid = molarity x volume
Number of moles of acid = 19.76 x 0.20 = 3.95mol
From the balanced reaction equation:
1 mole of acid reacts with 2 moles of the bases KOH
3.95mole of acid would react with 3.95moles x 2 of the base
Number of moles of reacting base = 7.90moles
To find the volume of base;
Volume of base = 
Volume =
= 30.40mL
Learn more:
Neutralization brainly.com/question/6447527
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