Answer:
r = -12cos(θ)
Step-by-step explanation:
The usual translation can be used:
Putting these relationships into the formula, we have ...
(r·cos(θ) +6)² +(r·sin(θ))² = 36
r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36
r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1
r(r +12cos(θ)) = 0
This has two solutions for r:
r = 0 . . . . . . . . a point at the origin
r = -12cos(θ) . . . the circle of interest
Answer:122
Step-by-step explanation:
Step-by-step explanation: need to find a basis for the solutions to the equation Ax = 0. To do this ... 0 0 0 1 −3. ⎤. ⎦. From this we can read the general solution, x = ⎡. ⎢. ⎢. ⎢. ⎢. ⎣ ... two vectors are clearly not multiples of one another, they also give a basis. So a basis ... 4.4.14 The set B = {1 − t2,t − t2,2 − 2t + t2} is a basis for P2.
3/4 times 3/2 (reciprocal of the second fraction) is 9/8 gallons per minute.
5/8 times 2/1 (reciprocal of the second fraction) is 10/8 gallons per minute
The second tank is filling faster.
Note:
The slope of a straight line passing through the points (x₁, y₁) and (x₂, y₂) is
The two given points are (-3,4) and (4,-1). Therefore the slope is
Answer:
