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anygoal [31]
3 years ago
10

1. I think the answer is 5/50 am I correct?

Mathematics
2 answers:
aliina [53]3 years ago
8 0

Answer:

5 x plus 50 I think but you ate right about it

lilavasa [31]3 years ago
3 0

Answer:

1. I think the answer is 5/50 I’m currect

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Sarah jogged 4.8 miles each day for 22 days last month. How many miles did Sarah jog in total?
solong [7]

Answer:

105.6

hope this helps

have a good day :)

Step-by-step explanation:

8 0
3 years ago
PLEASEEE HELP!!!! WILL GIVE BRAINLEST<br> SHOW ur work!
IgorLugansk [536]

Answer:

The answer is 16.

Step-by-step explanation:

When you calculate the ratio of 42:28, you would get 3:2. divide 24 by 3, and you get 8. Then multiply 2 by 8 you get 16.

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3 years ago
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
Which of the following options have the same value as 20% of 45?
elena-s [515]
B is one of them, i'm not sure how any of the other answers are equivalent to 20% of 45 which is 8.

3 0
3 years ago
Read 2 more answers
Solve for x please show work
Vanyuwa [196]

Answer:

it is 10 d a d a p a p a

Step-by-step explanation:

5 0
3 years ago
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