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3 years ago

Exercise - 41 Express the following angles into sexagesimal seconda. 20° 20

Mathematics

1 answer:

liubo4ka [24]3 years ago

5 0

Answer:

202000''

Step-by-step explanation:

(20*100*100)+(20*100)

200000+2000

202000

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Whats the vertex at of y-13=2(x+4)^2

Kipish [7]

The vertex form:
$y=a(x-h)^2+k$
(h,k) - the coordinates of the vertex

$y-13=2(x+4)^2 \\
y=2(x+4)^2+13 \\
y=2(x-(-4))^2+13 \\ \\
h=-4 \\ k=13$

The coordinates of the vertex are (-4,13).

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3 years ago

Solve the equation 14(3x-1)=2x-23

irina1246 [14]

Answer:

$x=\frac{-9}{40} \\$

Step-by-step explanation:

Given Equation:

$14(3x-1)=2x-23$

Solving the bracket on L.H.S

$(14)(3x)-1(14)=2x-23$

$42x-14=2x-23$

Taking the terms of 'x' to one side and the constants to other side

$42x-2x=-23+14\\\\40x=-9\\\\x=\frac{-9}{40} \\$

The value of 'x' after solving the equation is:

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3 years ago

Both circle A and circle B have a central angle measuring 140°. The ratio of the radius of circle A to the radius of circle B is

beks73 [17]

Let
rA--------> radius of the circle A
rB-------> radius of the circle B
LA------> the length of the intercepted arc for circle A
LB------> the length of the intercepted arc for circle B

we have that
rA/rB=2/3--------> rB/rA=3/2
LA=(3/4)π

we know that
if Both circle A and circle B have a central angle , the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the length of circle A to the length of circle B
rA/rB=LA/LB--------> LB=LA*rB/rA-----> [(3/4)π*3/2]----> 9/8π

the answer is
the length of the intercepted arc for circle B is 9/8π

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3 years ago

Exercise - 41 Express the following angles into sexagesimal seconda. 20° 20​

Exercise - 41 Express the following angles into sexagesimal seconda. 20° 20