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insens350 [35]
3 years ago
14

Simplify. (½) ²− 6(2−2/3)

Mathematics
1 answer:
zzz [600]3 years ago
8 0
\left(\dfrac{1}{2}\right)^2-6\cdot\left(2-\dfrac{2}{3}\right)\\\\=\dfrac{1}{4}-6\cdot2+6\cdot\dfrac{2}{3}=\dfrac{1}{4}-12+2\cdot2\\\\=\dfrac{1}{4}-12+4\\\\=\dfrac{1}{4}-8=\boxed{-7\frac{3}{4}}
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Points A, B and C lie on a circle, centre O.<br> Angle AOC = 142°.<br> Find the value of y.
aksik [14]

The value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

Let suppose that quadrilateral OABC is a parallelogram. Then, the following conditions must be fulfilled:

  1. \overline {OA} \cong \overline {BC}
  2. \overline{AB} \cong \overline{OC}
  3. \angle AOC \cong \angle ABC

In addition, if we have a rhombus we have the additional condition as A, B and C lie on the circle:

\overline{OA} \cong \overline {AB} \cong \overline {BC} \cong \overline{OC} (4)

If we know that \angle AOC = 142^{\circ}, then the value of \angle ABC = y = 142^{\circ}.

Based on all these finding, we conclude that the value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

To learn more on parallelograms, we kindly invite to check this verified question: brainly.com/question/555469

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