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insens350 [35]
3 years ago
14

Simplify. (½) ²− 6(2−2/3)

Mathematics
1 answer:
zzz [600]3 years ago
8 0
\left(\dfrac{1}{2}\right)^2-6\cdot\left(2-\dfrac{2}{3}\right)\\\\=\dfrac{1}{4}-6\cdot2+6\cdot\dfrac{2}{3}=\dfrac{1}{4}-12+2\cdot2\\\\=\dfrac{1}{4}-12+4\\\\=\dfrac{1}{4}-8=\boxed{-7\frac{3}{4}}
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286,489 is an odd number.how many times greater is the ten thousand place than the 8 in the tens place ?
jonny [76]

We're comparing 80,000 with 80.

One way to do this is divide the two numbers: 80,000/80 = 1000.

80,000 is one thousand times greater than 80.

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4 years ago
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HELP! I need 2 problems for this question!
larisa86 [58]
First are you in connections academy? I am, I had this disscussion before.
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3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra
Rainbow [258]

Answer:

x = t

y = 1 - t

z = 2t

Step-by-step explanation:

Given

x=t

y=e^{-t}

z=2t-t^2

(0, 1, 0)

The vector equation is given as:

r(t) = (x,y,z)

Substitute values for x, y and z

r(t) = (t,\ e^{-t},\ 2t - t^2)

Differentiate:

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

The parametric value that corresponds to (0, 1, 0) is:

t = 0

Substitute 0 for t in r'(t)

r'(t) = (1,\ -e^{-t},\ 2 - 2t)

r'(0) = (1,\ -e^{-0},\ 2 - 2*0)

r'(0) = (1,\ -1,\ 2 - 0)

r'(0) = (1,\ -1,\ 2)

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

r(t) = a + tv

Such that:

a = (0,1,0) and v = r'(0) = (1,-1,2)

The equation becomes:

r(t) = (0,1,0) + t(1,-1,2)

r(t) = (0,1,0) + (t,-t,2t)

r(t) = (0+t,1-t,0+2t)

r(t) = (t,1-t,2t)

By comparison:

r(t) = (x,y,z) and r(t) = (t,1-t,2t)

The parametric equations for the tangent line are:

x = t

y = 1 - t

z = 2t

7 0
3 years ago
3i (2i-4)<br><br> Show steps and answer
Sloan [31]

Answer:

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3i×2i =6i^2

3i×4 =12i

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What is the measure of STR?
aliina [53]
The measurement of STR is 24 degrees
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